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anonymous
 4 years ago
based on you guy's knowledge of limits explain(without using algebra or tables) why the two functions: g(x)=(sqroot(100+x)(sqroot(100x))/x and
G(x)=(sqroot(100+x^n)(sqroot(100+x^n))/x^n should have the same limit as x approaches 0
anonymous
 4 years ago
based on you guy's knowledge of limits explain(without using algebra or tables) why the two functions: g(x)=(sqroot(100+x)(sqroot(100x))/x and G(x)=(sqroot(100+x^n)(sqroot(100+x^n))/x^n should have the same limit as x approaches 0

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I guess its because as x approaches 0 , x^n also approaches 0  though i'm not not absolutely sure about that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Because x^n > 0 whenever x goes to zero for any n>0
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