anonymous
  • anonymous
based on you guy's knowledge of limits explain(without using algebra or tables) why the two functions: g(x)=(sqroot(100+x)-(sqroot(100-x))/x and G(x)=(sqroot(100+x^n)-(sqroot(100+x^n))/x^n should have the same limit as x approaches 0
Mathematics
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anonymous
  • anonymous
based on you guy's knowledge of limits explain(without using algebra or tables) why the two functions: g(x)=(sqroot(100+x)-(sqroot(100-x))/x and G(x)=(sqroot(100+x^n)-(sqroot(100+x^n))/x^n should have the same limit as x approaches 0
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
I guess its because as x approaches 0 , x^n also approaches 0 - though i'm not not absolutely sure about that
anonymous
  • anonymous
Because x^n -> 0 whenever x goes to zero for any n>0

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