Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

yup

ok i got it now

jimmy can you help me with this
find the slope of the tangent line of f(x)= 2x^2-x+3

best written as (6/7) x though jinnie - so its not confused with 4 divided by 7x

6/7?

yea ok
find derivative of f(x)
f'(x) = 4x - 1
- thats it

so for example the slope of tangent at x = 1 = 4(1) - 1 = 3

sorry i meant (4/7)

so i must find the derivative first which is 2x-1+0

of 2x^2-x+3

yeah - but its 4x - 1
The derivative at a point on a curve is slope of the tangent at that point

oh yea you have to multiply ok i got it

can i continue with that or is that where it stops

you can simplify that
y - 4 = 3x - 3
y = 3x + 1

alright thanks

how did you get the slope of 3 btw

yw - hope this helps

ok thanks