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anonymous
 4 years ago
2x+4yz=7
2x4y+2z=6
x+4y+z=0
anonymous
 4 years ago
2x+4yz=7 2x4y+2z=6 x+4y+z=0

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0assum first with second 2x+4yz=7 2x4y+2z=6  4x 0 +z=1 and assum second with 3rd 2x4y+2z=6 x+4y+z =0  3x+ 0 3z=6 4x+z=1 multiply by 3 3x+3z=6 12x3z=3 3x+3z=6  assum 9x 0 =9 9x=9 x= 9/(9) =1 x=1 4(1)+z=1 so 4+z=1 so z=3 x+4y+z=0 1+4y3=0 4y=2 y=2/4 = 1/2 x=1 y=1/2 z=3
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