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anonymous
 4 years ago
Geometry and Ratio problem!!! Help!!!
anonymous
 4 years ago
Geometry and Ratio problem!!! Help!!!

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The figure ABCDEF below is a regular hexagon, and point P lies on side AB, with AP=3 cm and PB=1cm. Line PE meets AD at Q. What is the ratio of the area of quadrilateral AQEF to the area of hexagon ABCDEF? Express your answer as a common fraction.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327787358619:dw

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0All you do is find the areas and put them in fraction form

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how do I find the area of AQEF?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Can you give me some hints? Please.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Wait, so all the side lengths are 3? Isn't it 4?

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0oh okay, I didn't read that indepth. This is different

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0You have to find the area of the hexagon first. There's no way to avoid that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Area of the hexagon = dw:1327788115227:dw

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0I don't have a solid approach to this. Sorry bud

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0I can take a look at it later maybe.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh, ok. Thanks for trying though.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0AD splits the hex into two halves. That might help.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok, I will keep trying.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Area of hexagon equals 24sqrt{3}, so ABCD equals 12sqrt{3} and ADEF equals 12 sqrt{3} as well.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0find the heigh of AE, calcuate the area of triangle APE and AFE...then you have an answer i guess

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the height of AE is 4sqrt{3}, APE is 6sqrt{3}. But how do I find AFE and AQP then?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327789175987:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I made an mistake, AEF should be 4sqrt{3}.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0asnaseer, moneybird, and mertsj should be able to figure this out.

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1I think matematika and yociyoci are doing well so far...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im not sure....but isn't there formula for calulating triangle if you know one side and angels?maybe with help of this you can find out area of this one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But I don't know that formula, is there another approach?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You can find the height of triangle EDQ

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0triangle EDQ and triangle PAQ are similar

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so the height of EDQ isdw:1327790090893:dw ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0AD splits the hexagon in halves so quadrilateral AQEF = quadrilateral AFED  triangle FDQ

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1you mean  EDQ moneybird

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is triangle EDQ eqauls to 32sqrt{3}/7 ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ya dw:1327790174473:dw From midpoint of ED to midpoint of AB is 4 sqrt(3)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now use ratio to find the height of triangle EDQ and triangle APQ

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{4}{h} = \frac{3}{4\sqrt{3}h}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I don't quite understand what you just did. Can you clarify, please?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0when you cut the hexagon into six equal pieces, you take out one of the piece, which is a triangle

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327790925432:dwso the area of the hexagon is 24 sqrt(3) ratio is

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok, i understand. thank you very much, guys!!!! I appreciated!!!

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.1very well explained moneybird
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