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anonymous

  • 4 years ago

Solve the system to find the pivots when 2u-v=0, -u+2v-w=0, -v+2w-z=0, -w+2z=5. You may carry the right hand side as a fifth column

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  1. TuringTest
    • 4 years ago
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    It's a system with the same number of variables as equations, so it can be soved I like putting this many variables in matrix format:|dw:1327789604575:dw|now just pick a method: elimination, Cramer's rule, etc.

  2. TuringTest
    • 4 years ago
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    solved*

  3. TuringTest
    • 4 years ago
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    ...of course when I get tired of doing that all day I just have wolfram do it :P http://www.wolframalpha.com/input/?i=solve%202u-v%3D0%2C%20-u%2B2v-w%3D0%2C%20-v%2B2w-z%3D0%2C%20-w%2B2z%3D5&t=crmtb01

  4. TuringTest
    • 4 years ago
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    If you are looking to avoid wolfram you could use Cramer's rule for the setup, and the method of cofactors to do the determinants. There may be an easier way though

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