ok i need a lil clarificationon this problem...the answer i got was marked wrong on my test but i cant seem to come up with the answer they said was correct. heres the question...
Write an equation of the line containing the given point and parallel to the given line.
(2,-8) ; 2x-7y=3
Stacey Warren - Expert brainly.com
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|dw:1327791230103:dw|first i solved the equation for y to put it in slope intercept form
i know that for my new equation for a parallel line the slope stays the same so i got
y=(2/7)x+b then i inserted the point values into the equation for x and y and got
then i plugged this b value into the equation to give me
but the test said the "correct" answer was y= (2/7)x-(60/7)
so can someone please tell me where i went wrong?
7y = 2x - 3
y = (2/7) x - 3/7
so the slope of ur line will be 2/7
it passes thru point (2,-8) so
y -(-8) = 2/7 (x - 2)
y + 8 = 2/7(x-2)
multiply thru by 7
7y + 56 = 2x - 4
7y = 2x - 60