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anonymous
 4 years ago
How would you go about finding the solution to this system of three equations in 3 variables?
anonymous
 4 years ago
How would you go about finding the solution to this system of three equations in 3 variables?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can i see those three equations it might help

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02x  y + z = 7 x + 2y  5z = 1 x  y = 6

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you can probably use the last equation and make x = y + 6 substitute that value into the first or second equation and find y = and then substitue that back into the last equation to get x = i did this 3 years ago in my freshman year but you can try it. If you want i will try to figure this question out and tel you the answer 10 minutes from now? :O

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its okay, you don't have to work it out hun (:

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just to be on the safe side :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Here it goes: Label all the equations by numbers...gonna be useful 2x  y + x =7 (1) x + 2y  5z = 1 (2) x  y = 6 (3) find a equation with a coefficient you can eliminate using another equation I chose (1) and (2) Make one variable have the same coefficient Since the third equation consist only of x and y > we need to eliminate z in this one 2x  y + z = 7 (1) x 5 x + 2y 5z = 1 (2) 10x  5y + 5z = 35 + x + 2y 5z = 1  11x  3y = 34 Now that you made an equation consisting of x and y: solve for one variable using substitution or elimination rearrange (3) x  y = 6 x = y + 6 substitute x = y  6 into 11x  3y = 34 11x  3y = 34 11(y + 6)  3y = 34 11y + 66  3y = 34 * combine the like terms and move 66 to the right side 11y  3y = 34  66 8y = 32 * Divide both sides by 8 y = 4 one variable down two more to go substitute y = 4 into (3). Make sure you use the original equation and not the re arranged one :D x  y = 6 x  (4) = 6 x + 4 = 6 * Move 4 over to the other side x = 6  4 x = 2 Alright now you got two variables and you need the last one :D substitute x = 2 and y = 4 into equation (2) 2x  y + z = 7 (2) 2(2)  (4) + z = 7 4 + 4 + z = 7 8 + z = 7 z = 7  8 z = 1 You got all three variables. Write your therefore statement. Therefore, x = 2, y = 4 and z = 1 Moral of the question: the order matters
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