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ofree18

  • 2 years ago

identify the solutions to the equation 3x^2-4x=-2 when you solve by using the quadratic formula

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  1. Mertsj
    • 2 years ago
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    First add 2 to both sides so you can have the equation in the correct form.

  2. Mertsj
    • 2 years ago
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    Then you will see that a = 3, b = -4 and c = 2

  3. Mertsj
    • 2 years ago
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    Now plug those values into the quadratic formula.

  4. ofree18
    • 2 years ago
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    which is?

  5. Mertsj
    • 2 years ago
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    \[x=\frac{-b \pm \sqrt{b ^{2}-4ac}}{2a}\]

  6. ofree18
    • 2 years ago
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    the options look like this

  7. ofree18
    • 2 years ago
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    |dw:1327793835199:dw|

  8. BlingBlong
    • 2 years ago
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    No real solutions to your probelm

  9. BlingBlong
    • 2 years ago
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    thus just write that unless your teacher specified that he wants you to answer in imaginary numbers

  10. ofree18
    • 2 years ago
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    no it is one of those answers

  11. ofree18
    • 2 years ago
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    yes it can be imaginary

  12. myininaya
    • 2 years ago
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    \[x=\frac{-(-4) \pm \sqrt{(-4)^2-4(3)(2)}}{2(3)}\]

  13. myininaya
    • 2 years ago
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    same thing as before simplify

  14. ofree18
    • 2 years ago
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    what do i do with the squareroot of-8?

  15. myininaya
    • 2 years ago
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    \[\sqrt{-8}=i \sqrt{8}= i \sqrt{4} \sqrt{2} =i (2) \sqrt{2}=2 i \sqrt{2}\]

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