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anonymous
 4 years ago
solve using elimination: u+v+w=6, u+2v+2w=11, 2u+3v4w=3.....i keep getting the wrong answers according to wolf ram and i am not sure why
anonymous
 4 years ago
solve using elimination: u+v+w=6, u+2v+2w=11, 2u+3v4w=3.....i keep getting the wrong answers according to wolf ram and i am not sure why

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campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.0label your equations (1), (2), (3) and reduce the 3 equations to 2 equations in 2 unknowns.. Eliminate u Equation (1)  Equation (2) gives v w = 5 (4) 2 x Equation (1)  Equations(3) gives v + 6w = 9 (5) Eliminate v 1 x Equation (4) + equation (5) = 7w = 14 Substitute to get the other pronumerals. My solution is u =1, v = 3 and w = 2

phi
 4 years ago
Best ResponseYou've already chosen the best response.0u+v+w=6, u+2v+2w=11, 2u+3v4w=3 just the coefficients, in order u v w constant 1 1 1 6 1 2 2 11 2 3 4 3 multiply the top row by 1 and add to the 2nd row ( we add 1 1 1 6 to the 2nd row) 1 1 1 6 0 1 1 5 2 3 4 3 multiply the top row by 2 and add to the 3rd row (we add 2 2 2 12 to the 3rd row) 1 1 1 6 0 1 1 5 0 1 6 9 multiply the 2nd row by 1 and add to the 3rd row (add 0 1 1 5 to the 3rd row) 1 1 1 6 0 1 1 5 0 0 7 14 backsolve (start at the bottom) w= 14/7 = 2 v + 2= 5, v= 3 u+3+2=6, u = 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Answer : u = 1 v= 3 w = 2
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