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anonymous

  • 4 years ago

can someone help me with simplifying radicals?

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  1. anonymous
    • 4 years ago
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    Go for it.

  2. precal
    • 4 years ago
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    yes, what do you have?

  3. anonymous
    • 4 years ago
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    Well this worksheet that I have to do has some problems that I have no idea on how to do how would I simplify one that was 6 square root 200

  4. precal
    • 4 years ago
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    \[6\sqrt{200}\] is this the problem?

  5. anonymous
    • 4 years ago
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    yes

  6. precal
    • 4 years ago
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    \[6\sqrt{2*100}\] \[6*10\sqrt{2}\] \[60\sqrt{2}\]

  7. Akshay_Budhkar
    • 4 years ago
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    \[\sqrt{ 200 }= \sqrt 2 \times \sqrt{100} = 10 \times \sqrt2\]

  8. anonymous
    • 4 years ago
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    I have a few more questions. is that ok?

  9. precal
    • 4 years ago
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    go for it @Akshay Budhkar What happened to your 6?

  10. anonymous
    • 4 years ago
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    they must have lost it :)

  11. Akshay_Budhkar
    • 4 years ago
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    lol i was gonna write it in the next step but u got the answer before it :)

  12. precal
    • 4 years ago
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    I can only help for a couple of minutes (maybe 10)

  13. Akshay_Budhkar
    • 4 years ago
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    couple is not equal to 10

  14. precal
    • 4 years ago
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    ok but time is going fast and I have other things to do....

  15. anonymous
    • 4 years ago
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    anyway... how would you do (2 square 6 times 3 square root 2?

  16. anonymous
    • 4 years ago
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    and 16/81 all in a square root

  17. anonymous
    • 4 years ago
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    or 3/ the square root of 2

  18. anonymous
    • 4 years ago
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    and the square root of 6 over 3 square root 2

  19. anonymous
    • 4 years ago
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    square root of 4 over square root 11

  20. precal
    • 4 years ago
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    \[2^2(6*3\sqrt{2})\] is this problem? Use the Equation editor on the lower left side to input your problems

  21. anonymous
    • 4 years ago
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    \[(2\sqrt{6})(3\sqrt{2})\]

  22. precal
    • 4 years ago
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    \[\left( 2\sqrt{11} \right)/11\]\[\sqrt{4}/\sqrt{11}\] \[2/\sqrt{11}\] That is the solution for one of the problems Gotta go!

  23. anonymous
    • 4 years ago
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    thanks:)

  24. precal
    • 4 years ago
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    \[6\sqrt{12}\] \[6\sqrt{4*3}\] \[6*2\sqrt{*3}\] \[12\sqrt{*3}\] ok that is for the one you posted correctly

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