anonymous
  • anonymous
can someone help me with simplifying radicals?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Go for it.
precal
  • precal
yes, what do you have?
anonymous
  • anonymous
Well this worksheet that I have to do has some problems that I have no idea on how to do how would I simplify one that was 6 square root 200

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More answers

precal
  • precal
\[6\sqrt{200}\] is this the problem?
anonymous
  • anonymous
yes
precal
  • precal
\[6\sqrt{2*100}\] \[6*10\sqrt{2}\] \[60\sqrt{2}\]
Akshay_Budhkar
  • Akshay_Budhkar
\[\sqrt{ 200 }= \sqrt 2 \times \sqrt{100} = 10 \times \sqrt2\]
anonymous
  • anonymous
I have a few more questions. is that ok?
precal
  • precal
go for it @Akshay Budhkar What happened to your 6?
anonymous
  • anonymous
they must have lost it :)
Akshay_Budhkar
  • Akshay_Budhkar
lol i was gonna write it in the next step but u got the answer before it :)
precal
  • precal
I can only help for a couple of minutes (maybe 10)
Akshay_Budhkar
  • Akshay_Budhkar
couple is not equal to 10
precal
  • precal
ok but time is going fast and I have other things to do....
anonymous
  • anonymous
anyway... how would you do (2 square 6 times 3 square root 2?
anonymous
  • anonymous
and 16/81 all in a square root
anonymous
  • anonymous
or 3/ the square root of 2
anonymous
  • anonymous
and the square root of 6 over 3 square root 2
anonymous
  • anonymous
square root of 4 over square root 11
precal
  • precal
\[2^2(6*3\sqrt{2})\] is this problem? Use the Equation editor on the lower left side to input your problems
anonymous
  • anonymous
\[(2\sqrt{6})(3\sqrt{2})\]
precal
  • precal
\[\left( 2\sqrt{11} \right)/11\]\[\sqrt{4}/\sqrt{11}\] \[2/\sqrt{11}\] That is the solution for one of the problems Gotta go!
anonymous
  • anonymous
thanks:)
precal
  • precal
\[6\sqrt{12}\] \[6\sqrt{4*3}\] \[6*2\sqrt{*3}\] \[12\sqrt{*3}\] ok that is for the one you posted correctly

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