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anonymous
 4 years ago
can someone help me with simplifying radicals?
anonymous
 4 years ago
can someone help me with simplifying radicals?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well this worksheet that I have to do has some problems that I have no idea on how to do how would I simplify one that was 6 square root 200

precal
 4 years ago
Best ResponseYou've already chosen the best response.0\[6\sqrt{200}\] is this the problem?

precal
 4 years ago
Best ResponseYou've already chosen the best response.0\[6\sqrt{2*100}\] \[6*10\sqrt{2}\] \[60\sqrt{2}\]

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{ 200 }= \sqrt 2 \times \sqrt{100} = 10 \times \sqrt2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I have a few more questions. is that ok?

precal
 4 years ago
Best ResponseYou've already chosen the best response.0go for it @Akshay Budhkar What happened to your 6?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0they must have lost it :)

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.0lol i was gonna write it in the next step but u got the answer before it :)

precal
 4 years ago
Best ResponseYou've already chosen the best response.0I can only help for a couple of minutes (maybe 10)

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.0couple is not equal to 10

precal
 4 years ago
Best ResponseYou've already chosen the best response.0ok but time is going fast and I have other things to do....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0anyway... how would you do (2 square 6 times 3 square root 2?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and 16/81 all in a square root

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0or 3/ the square root of 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and the square root of 6 over 3 square root 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0square root of 4 over square root 11

precal
 4 years ago
Best ResponseYou've already chosen the best response.0\[2^2(6*3\sqrt{2})\] is this problem? Use the Equation editor on the lower left side to input your problems

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[(2\sqrt{6})(3\sqrt{2})\]

precal
 4 years ago
Best ResponseYou've already chosen the best response.0\[\left( 2\sqrt{11} \right)/11\]\[\sqrt{4}/\sqrt{11}\] \[2/\sqrt{11}\] That is the solution for one of the problems Gotta go!

precal
 4 years ago
Best ResponseYou've already chosen the best response.0\[6\sqrt{12}\] \[6\sqrt{4*3}\] \[6*2\sqrt{*3}\] \[12\sqrt{*3}\] ok that is for the one you posted correctly
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