A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Can someone help me with eigenvalues and eigenvectors?
anonymous
 4 years ago
Can someone help me with eigenvalues and eigenvectors?

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I need help with problem number 6

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Use: \[det(A\lambda I) = 0\] to find the eigenvalues. For two by two matrices I think you will get two values of lambra (as a quadratic in lambda will come out).

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I basically need help with part C

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You have to find a vector X such that \[ AX=\lambda X \]

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[\det(AI\lambda)=\det\left[\begin{matrix}2\lambda & 2 \\ 2 & 2\lambda\end{matrix}\right]=42\lambda+\lambda^24\]sorry gotta eat!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0For the corresponding eigenvectors, I think it's a case of finding X in \[A\lambda I = X\] when you know the two values of lambda...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Turing its the opposite

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1you have I*IambdaA I'm guessing, it's the same it is the same

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh sorry \[(A\lambda I)X = 0\] (the ero matrix)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohhh ya that is the one i have in my textbook

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Check out this example : http://en.wikipedia.org/wiki/Eigenvalues_and_eigenvectors#Worked_example

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks I figured it out :D

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.2For \( \lambda=0 \) reduced matrix is \[\left[\begin{matrix}1 & 1 \\ 0 & 0\end{matrix}\right]\]which gives an eigenvector of (1,1). For \( \lambda=4 \), the reduced matrix is\[\left[\begin{matrix}1 & 1 \\ 0 & 0\end{matrix}\right]\]whose eigenvector is (1,1).

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks Guys :D I really appreciate ur help
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.