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anonymous
 4 years ago
can someone help me understand on how to simplify radicals?
anonymous
 4 years ago
can someone help me understand on how to simplify radicals?

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saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.0Where are u stuck? do u have any examples?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how would I simplify 16/81 all under a square root simble?dw:1327798829785:dw

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{\frac{16}{81}}\]That right?

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.0That can we written as, \[\frac{\sqrt{16}}{\sqrt{81}}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so then it would be like 4 over 9?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327799041137:dw

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.0Yes 4/9 is correct. but How u got 4/9 ? u simplified using the square root.. So the cancel will be cancelled now.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh that makes sense, thank you:) would you be able to help me out with a few more problems?

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{\frac{16}{81}} \to \frac{\sqrt{16}}{\sqrt{81}} \to \frac 49 \]

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.0Welcome. How many do u have? i will help u as much as i can.

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.0i dont have much time though.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok, then ill ask you the ones that are more difficult than others

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.0Feel free to do so.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how would i simplify dw:1327799236709:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and i also am wondering how I would solve\[2\sqrt{3}\div3\sqrt{2}\]

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{75} \text{ can be written as,} \sqrt{ 25 \times 3} \to 5 \sqrt3\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok i got that one thanks:)

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.0So now u cann those.

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.0For the second one, That is simplified, but indirectly.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0one more question after the last one i posted is How do i simplify questions that have like 10 over square root 5dw:1327799591814:dw

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{10}{\sqrt5} \times \frac{\sqrt5}{\sqrt5}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so for the one thats simplified i would just write simplfyied?

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.0Idk.. have you guys studied rationalizing?

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{2\sqrt3}{3 \sqrt 2}\times \frac{3 \sqrt2}{3 \sqrt2}\]Now u may solve this.

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.0Nope, simply multiply. You ONLY cross multiply when there's a "=" sign in between.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Just a nice couple of things about radicals. If a and b are numbers then \[\sqrt{ab} = \sqrt{a}\sqrt{b}\] \[\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}\] and if n and m are any numbers, then \[n\sqrt{a} + m\sqrt{a} = (n+m)\sqrt{a}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0should add \[b \neq 0\] for that second one..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you help me with a problem?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what was the second one?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the second one is the fraction, one must never divide by zero. Also a and b are obviously nonnegative (unless it's an odd radical)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0um can you help me with a few more questions?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0? what's the problem?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how would i simplify dw:1327800649423:dw

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.0Rationalize it, \[\frac{7}{2 \sqrt2} \times \frac{2 \sqrt2}{2 \sqrt2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0why do you multiply it?

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.0Whenever u have a sqrt in bottom part. we always do it that way to simplify it. The method is known as rationalizing. in which we multiply and divide the fraction by the denomiator.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok, so im stupid, so can you help me multiply that?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok thanks, thats helpful :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0on that last one it was sufficient to just multiply by \[\frac{\sqrt{2}}{\sqrt{2}}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0isdw:1327802012909:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok, suppose you have a fraction like this \[\frac{7}{2\sqrt{2}}.\] You want to rationalise the denominator, which means  make the number on the bottom into something without roots. Now multiplying this fraction by 1 will not change it. Notice that \[1 = \frac{\sqrt{2}}{\sqrt{2}}\] and this is true for anything: something divided by itself equals 1. Therefore \[\frac{7}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}} = \frac{7\sqrt{2}}{2(\sqrt{2})^2}\] Now the squared removes the square root and you are just left with 2: \[(\sqrt{2})^2 = 2\] So we get in the end: \[\frac{7\sqrt{2}}{4}\] and this is equal to what you started with, and the change we have made is we have rationalised the denominator.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That's wrong by the way, \[\sqrt{1} + \sqrt{1} = 2\sqrt{1}\] because there is two of them! and we know that \[\sqrt{1} = 1\] so \[\sqrt{1} + \sqrt{1} = 2\sqrt{1} = 2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and so the square root of 1 +the square root of 1 is 2?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes, since the square root of 1 is 1, so it reduces to 1+1!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ah, thank you:) I have now finished my math assignment. You have helped me so much, instead of just giving me the answers you helped me understand it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no problem! Hope it's been a help
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