anonymous
  • anonymous
Is this a contradiction? On this problem they ask: Use the definitions of the hyperbolic functions to find the following limit: lim x->infinity sinhx However the answer is either: lim x->0^- coth(x) = -infinity or lim x->0^+ coth(x) = infinity Anyone see what I'm doing wrong? I'm attaching the original problem
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
Any ideas?
anonymous
  • anonymous
i'm not sure what you're asking...

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anonymous
  • anonymous
are you sure the put the right attachment
anonymous
  • anonymous
I'm sorry, my bad, mistyped the uploaded file
1 Attachment
anonymous
  • anonymous
I'll take that as no one is sure what to do...
anonymous
  • anonymous
do you know the standard algebraic expressions for the hyperbolic functions?
anonymous
  • anonymous
x = sinh x = (e^x - e^-x)/2
anonymous
  • anonymous
* sinhx = sinh x = (e^x - e^-x)/2
campbell_st
  • campbell_st
well use the definition \[\sinh (x) = (e^x - e^(-x))/2\] so its the \[\lim_{x \rightarrow \infty} (e^x - e^(-x))/2\] rewriting \[\lim_{x \rightarrow \infty} e^x/2 - \lim_{x \rightarrow \infty} 1/(2e^x)\] 2nd part approaches 0 as x approaches infinity 1st part has approaches infinity
anonymous
  • anonymous
Ah, I see, thats kind of a strange problem
anonymous
  • anonymous
thanks!

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