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Do you have a Z-Score chart with you?
Wait, do you need a z-score chart?
No. i don't but the z score is 1.33 so I am guessing that the z score is negative but i am not sure
I always thought you could tell the if the z-score was positive or negative based on whether or not it had a negative sign in front of it...
I think that Since Z = (score-mean)/standard deviation, scores below the mean will have a negative value, and those above the mean will have a positive value.
weren't you told that the z-score is 1.33 > 0 (??)
You know about the graph/diagram right?
I was told that the z score was 1.33 which is 1.33 sd from the mean
Tim, I do not know about the graph/diagram
Broken Fixer do you think that I am correct that the z score is negative?
The graph you draw to solve problems usually.|dw:1327803029445:dw||dw:1327803073992:dw|
Thanks. I am still not sure if I am correct or not that my z score is negative value.
I think it's negative. But I don't know what the mean is. I think that the 1.33 is below the mean in this case thought. REally, I just don't know...
Thanks Tim. I agree. I believe that the 1.33 is below the mean of 17 thus making it a negative z score value, but I am not positive.
? I'm not sure I agree. If you're told that the z value is 1.33, then the z value is 1.33 > 0. If the z value was negative then the z value would have been -1.33.
That's what I thought at first. I was just getting confused though.
You're probably right.
What I was thinking Broken Fixer was. Since Z = (score-mean)/standard deviation, scores below the mean will have a negative value, and those above the mean will have a positive value. The mean is 17 and the z score is 1.33 the z value would be negative. The score was 21 and the mean was 17 standard deviation would be 3
when z = +1.33, you have a raw score that is 1.33 standard devs above the mean of the data
(am I missing part of the problem? where did 17 come from)
x = 21, sigma = 3, mu = 17 will give you z = +1.33 > 0 yes
The raw score is 21 you would subtract the mean of 17 from 21 and divide theat result (4) by the standard deviation of 3. The z-score of 1.33 tell
"z value" is a synonym for "z" is a synonym for "z score" and in this case it is 1.33 >0, because x is above the mean.
so are you saying that the z score in this case is positive?
I agree. I don't remember why I said negative. I know you disagree with this, and probably feel unsatisfied. Try looking through your textbook, or ask another source.
No I aactually get it now and agree. Aftere reading the book again and reading what you and Broken Fixer said, I agree that it is infact a positive value. Thanks for helping me through this!
Wonderful. Glad we helped.