• anonymous
Given A=integrate from 0 to 1 e^(-t^2) dt B=integrate from 0 to 1/2 e^(-t^2) dt compute the following dobule integral: 2 * integrate from -1/2 to 1 [integrate from 0 to x e^(-y^2) dy]dx as a function of A and B. Check that exists positives integers m and n and: I= m*A-n*B+e^(-1)-e^(-1/4) I tried reversing the integral order of the double integral to be able to compute easier, but it gave me: e^(-1)-e^(-1/4) + f(x) + c And if you made in the given order you got: e^(-1)-e^(-1/4) + f(y) + c And f(y) is where A and B came from, so I don't know how to solve this and... (to be continued)
Mathematics

Looking for something else?

Not the answer you are looking for? Search for more explanations.