Write the equation of the parabola that is congruent to y=x^2: a) has a minimum at (-3,0) b) has a maximum at (0,7) c) has a minimum at (5,6)

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Write the equation of the parabola that is congruent to y=x^2: a) has a minimum at (-3,0) b) has a maximum at (0,7) c) has a minimum at (5,6)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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a ) y = x -3 b) y = x + 7 c) y = (x -5) + 6
how did yu do it
ok so you take the maximum/ minimum of your equation and that will be your value for y = (x -h) + k k is your vertical translation and h is your horizantal translation

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Other answers:

wudn't it be y=(x+3)+k
oh my bad yeah the first one is y = (x -3) dont include the values if there are not given
no its a pos 3 not a neg 3
rem yu need to do it opp sign
my bad again y = (x+ 3)
LOL ok :D
ty

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