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anonymous
 4 years ago
Can someone help me figure out the eigenvector?
anonymous
 4 years ago
Can someone help me figure out the eigenvector?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327807423151:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the eigenvalue is 2 but I cant figure out the eigenvector

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0After subtracting the two matrices this is what I got dw:1327807555690:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What wld the answer be?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0preetha i thought u were going to chat with my older sis I hid her laptop so she wouldn't keep emailing you

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so the eigenvalue is 2. The eigenvector associated with 2 we will call X and we need: \[AX=2X\] 0 0 1 x 2x 0 1 4 y = 2y 0 0 1 z 2z So use matrix multiplication: z = 2x, y 4z = 2y, z=2z the last one implies z=0, and that implies that x=0. We have then y=2y which means y=0 too, so the 0 vector is the eigenvector associated with 2...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0maybe someone can verify this is right...I need to sleep!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok I am gonna look this over

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Obviously here X = (x,y,z)^t and you do this for each eigenvalue...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ummm i think u used the wrong matrice

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0cuzz I was using a diff method so that is y i showed u that matrice

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohh, you were using the method: \[(A2I)X = 0\] ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well use the correct matrix and just use my steps above as a blueprint, you can't go far wrong...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks I really appreciate ur help :DDDDDDDDDDD

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0NO I may have sounded rude but seriously I realy appreciate ur help :DDD

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327836820216:dw For \( \lambda = 2 \), since the first column is all zeroes, this would be your free variable and the eigenvector is (1,0,0). Have you found the eigenvector corresponding to the other eigenvalues?
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