Can someone help me figure out the eigenvector?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Can someone help me figure out the eigenvector?

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

|dw:1327807423151:dw|
the eigenvalue is 2 but I cant figure out the eigenvector
After subtracting the two matrices this is what I got |dw:1327807555690:dw|

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

What wld the answer be?
preetha i thought u were going to chat with my older sis I hid her laptop so she wouldn't keep emailing you
ok so the eigenvalue is 2. The eigenvector associated with 2 we will call X and we need: \[AX=2X\] 0 0 -1 x 2x 0 -1 -4 y = 2y 0 0 1 z 2z So use matrix multiplication: -z = 2x, -y -4z = 2y, z=2z the last one implies z=0, and that implies that x=0. We have then -y=2y which means y=0 too, so the 0 vector is the eigenvector associated with 2...
maybe someone can verify this is right...I need to sleep!
ok I am gonna look this over
Thanks :D
Obviously here X = (x,y,z)^t and you do this for each eigenvalue...
ummm i think u used the wrong matrice
cuzz I was using a diff method so that is y i showed u that matrice
ohh, you were using the method: \[(A-2I)X = 0\] ?
yes
well use the correct matrix and just use my steps above as a blueprint, you can't go far wrong...
idk okk whtvr
Thanks I really appreciate ur help :DDDDDDDDDDD
:D
NO I may have sounded rude but seriously I realy appreciate ur help :DDD
|dw:1327836820216:dw| For \( \lambda = 2 \), since the first column is all zeroes, this would be your free variable and the eigenvector is (1,0,0). Have you found the eigenvector corresponding to the other eigenvalues?

Not the answer you are looking for?

Search for more explanations.

Ask your own question