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anonymous
 4 years ago
Need help
please show me the steps so i know how to do this. Thanks.
4(x^3y^1)^2
anonymous
 4 years ago
Need help please show me the steps so i know how to do this. Thanks. 4(x^3y^1)^2

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King
 4 years ago
Best ResponseYou've already chosen the best response.0\[4(x ^{3y ^{1}})^{2}\] ???

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just put the y^1 down like the x is

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.1\[4(x^{3}y^{1})^{2}\]

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.1ok so we go on solving using the basic equation \[x^{a}={1 \over x^a}\]

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.1so we have \[x^{3}={ 1 \over x^3} , y^{1}={1 \over y^1}\]

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.1similarly we have\[(x^{3}y^{1})^{2}={1 \over(x^3y)^2}\]

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.1so your answer is \[4 x^6y^2\]

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.1sorry for late replies, net problem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes thank you i get it. thanks for all the steps
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