(50x^2y^-4 )^3 (200x^-2y^4)

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(50x^2y^-4 )^3 (200x^-2y^4)

Mathematics
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|dw:1327810924090:dw|
I'm lost as to how to start this one
simplify the brackets 1st (1/4 x^4 y^-8)^3 so (1/4)^3 x(4 x 3) y^(-8x3) = x^12/(64y^8)

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Other answers:

@campbell, follow solution of campbell. but, you could also distribute first the power to the numbers in the parenthesis. .
you mean ^3 to each number? including 50 and 200?
|dw:1327811295683:dw|
look at it as small problems inside the brackets... 50/200 = 1/4 x^2/x^-2 = x^(2 -(-2) = x^4 (index law for division, subtract the powers) y^-4 /y^4 = y ^(-4 -4) = y^-8 so inside is 1/4 x^4 y ^-8 then raise each term to the power of 3
1/4x^12y^24
x^12/(64 y^24) http://www.wolframalpha.com/input/?i=%5B%5B%2850%29%28x%5E2%29%28y%5E-4%29%5D+%2F%5B200%28x%5E-2%29%28y%5E4%29%5D%5D%5E3
|dw:1328051304954:dw| distribute the power to all terms inside the parenthesis. @rule of exponent- power rule

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