## anonymous 4 years ago y=2x²/3x²-16 What is the horizontal asymptote for the above function? y = _____

1. anonymous

2/3, as x approaches infinity, y will approach 2/3

2. campbell_st

divide top and bottom by x^2 gives 2/3 so thats the horizontal asymptote

3. Akshay_Budhkar

horizontal asymptote is when $x \rightarrow infinity$ so divide top and bottom by x^2 to get $y= {2 \over 3+{16 \over x^2} }$

4. anonymous

Assuming, of course, that the 16 is in the denominator.