anonymous
  • anonymous
I'm have a little problem grasping string concepts. Here's my other question. Please provide explanation. How many 8 bit strings contain exactly three 0’s?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
is 8 bit 8 binary digits?
anonymous
  • anonymous
yes
anonymous
  • anonymous
so there are 32 different possible combinations right?

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anonymous
  • anonymous
I think so yes.
anonymous
  • anonymous
Not 32 what was I thinking its 2^8 which is 256
anonymous
  • anonymous
can you explain please?
anonymous
  • anonymous
8 binary digits, each binary digit can be either 1 or 0, so I did 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 or 2^8
anonymous
  • anonymous
but the question ask how many 8 bit string contain EXACTLY three 0's?
anonymous
  • anonymous
right, but I'm just saying there are 256 possible combinations
anonymous
  • anonymous
I don't understand the concept. what if it asked contain EXACTLY four 0's would the answer be the same?
anonymous
  • anonymous
No no no no , 256 is not the answer. I'm just saying there are 256 DIFFERENT combinations for binary in 8 digits
anonymous
  • anonymous
OK so how do I figure out the answer?
anonymous
  • anonymous
Now to find the answer we can do 8 choose 3, it basically means how many combinations of 3 things can come out of 8 places for lack of better words. The formula for this is (for a choose b) |dw:1327813091899:dw|
anonymous
  • anonymous
a!/b! x (a-b)!
anonymous
  • anonymous
so try to figure it out now.
anonymous
  • anonymous
ok thank you
anonymous
  • anonymous
the answer is 56 i believe.
anonymous
  • anonymous
I don't under what (" for a choose b") mean. Can you explain please.
anonymous
  • anonymous
I just meant that when I say "a choose b" where a is bigger than b I mean the formula that I showed below

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