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anonymous
 4 years ago
How do I simplify this expression: √3 / √3 + √2? The answer is 3  √6... how?
anonymous
 4 years ago
How do I simplify this expression: √3 / √3 + √2? The answer is 3  √6... how?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is sqrt(2) in the denominator?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no, there's no root 2 in the denominator

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.2\(\sqrt 3/( \sqrt 3+ \sqrt 2)\) now multiply numerator and denominator by \(\sqrt 3 \sqrt 2\) we have \( \sqrt 3/( \sqrt 3 + \sqrt 2) *( \sqrt 3  \sqrt 2)/( \sqrt 3  \sqrt 2)\) we get \[ (32 \sqrt 6)/( 32)\] or \[32\sqrt 6\]

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.2sorry it'd be \[3\sqrt 6\]

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.2ignore the 2 int the last two steps

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but why is it 3  √6? Did you cancel something?

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.2when we multiplied \(\sqrt 3 \sqrt 2\) in the numerator and denominator , denominator became 1 . and numerator became \[3\sqrt 6\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you please show me? I'm still confused about what you just said.. so sorry D:

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It's called multiplying by the conjugate to rationalize the denominator

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I have it on my textbook but it's kind of confusing..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0because (ab)(a+b)=a^2b^2. Thus you eliminate the square roots from the denominator

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.2the numerator will become = 3 \(\sqrt 6\) denominatorw will be = 32= 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohhh.. kind of, aww man.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0why did you square it?

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.2when ever denominator has the form \(\sqrt a\pm \sqrt b\) multiply numerator and denominator by \(\sqrt a\mp \sqrt b\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohh, so the opposite.. and then?

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.2we'd in the denominator \[(\sqrt 3 + \sqrt 2)*( \sqrt 3  \sqrt 2)\] so this is in the form of (a+b)*(ab)= a^2b^2 so it'll become \[({\sqrt 3}^2  {\sqrt 2}^2)\] which is 32= 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohhh.. it's 32= 1? Not 3^2  2^2..?

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.2yeah , square of \(\sqrt a\) = a

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0square root of a number squared is the number itself

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes I did! thank you!
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