A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
As you are driving one day, you pass a construction site and stop to watch for a few minutes. A crane is lifting a batch of bricks on a pallet to an upper floor of the building. Suddenly a brick falls off the rising pallet. You were looking at your watch and measure that it takes 2.5 s for the brick to hit the ground. A falling brick can be dangerous, and you wonder how fast the brick was going when it hit. The crane has height markings and you see the brick fell off the pallet at a height of 22 m above the ground.
anonymous
 4 years ago
As you are driving one day, you pass a construction site and stop to watch for a few minutes. A crane is lifting a batch of bricks on a pallet to an upper floor of the building. Suddenly a brick falls off the rising pallet. You were looking at your watch and measure that it takes 2.5 s for the brick to hit the ground. A falling brick can be dangerous, and you wonder how fast the brick was going when it hit. The crane has height markings and you see the brick fell off the pallet at a height of 22 m above the ground.

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0v= change in distance / change in time. v= (22m  0m) / (2.5s  0s) v= 22m / 2.5s v= 8.8 m/s

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.0Smitm has given average speed of the brick for some reason... \[v=gt=9.8(2.5)=24.5m/s\]should the speed it hits the ground with. Though what's curious is that doesn't correspond to a 22 meter fall. Imformation seems excessive and contradictory.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.