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anonymous
 4 years ago
Integrate with steps
anonymous
 4 years ago
Integrate with steps

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{2\pi} \cos^2 (2\theta) d \theta\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So it becomes \[1/2 + 1/2 \cos (4 \theta)\] ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Um... Something's wrong with what I'm doing. The original question is to find the area of one of the clovers of \[r = \cos2 \theta\] So I did the integration of 0 to 2pi of the equation squared. I then divided by 1/4 to get 1 clover. But I got pi/4 instead of the answer pi/8

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.1remember it is \[\frac12\int_a^b r^2\,d\theta\] did you include the 1/2?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yeah, I forgot that. Ah, just woke up. Thanks.
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