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anonymous

  • 4 years ago

How do we find the value of k?

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  1. anonymous
    • 4 years ago
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    \[(3x+k)^3 + (4x-7)^2 \]

  2. anonymous
    • 4 years ago
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    has a remainder of 33 when divided by (x-3), how do we find the value of k?

  3. A_clan
    • 4 years ago
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    (3x+k)3+(4x−7)2 + 33 ---------------------- = some Integer , say I (x-3)

  4. anonymous
    • 4 years ago
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    why did you add 33 to the expression?

  5. A_clan
    • 4 years ago
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    Because 33 remained when we divided the expression by (x-3). So adding it to the expression will cause the expression to be completely divisible by (x-3).

  6. A_clan
    • 4 years ago
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    Sorry, it had to be subtracted.

  7. anonymous
    • 4 years ago
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    :o yeah

  8. A_clan
    • 4 years ago
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    (3x+k)3+(4x−7)2 - 33 ---------------------- = some Integer , say I (x-3)

  9. anonymous
    • 4 years ago
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    whats \[(3x+k)^3 ?\]

  10. A_clan
    • 4 years ago
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    Expanding it is the only way it seems. (a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3

  11. anonymous
    • 4 years ago
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    i've expanded it, but now im lost. how do we find k from here?

  12. anonymous
    • 4 years ago
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    a_clan, do u know how to solve this using the remainder theorem? :)

  13. A_clan
    • 4 years ago
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    f(x)=(3x+k)^3+(4x−7)^2 According to remainder theorem, f(3) = 33 (9+k)^3 + (12 - 7)^2 = 33 Rest is simple calculation.

  14. anonymous
    • 4 years ago
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    I got f(x) = 721 + k^3 is it incorrect?

  15. A_clan
    • 4 years ago
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    k^3 + 27k^2 + 243k + 721 = 0

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