A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
The remainder theorem? helpp, thanks :)
anonymous
 4 years ago
The remainder theorem? helpp, thanks :)

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(3x+k)^3 + (4x7)^2 has a remainder of 33 when divided by x3. what is k? :)

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.6so substitute x = 3 into the polynomial (3x3 +k)^3 + (4 x 3  7)^2 = 33 (9 + k)^3 + (5)^2 = 33 (9 +k)^3 = 8 take cube root of both sides (9 + k) = 2 I'll let you find k

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1we are given that on division we get remainder of 33 so we have (3x+k)^3+(4x7)^2=(Ax^+Bx+C)(x3)+33 A, B and C are constants now put x=3 in the above equation we'll get (9+k)^3+(127)^2=0+33 (9+k)^3+25=33 (9+k)^3=8 8=2^3 so (9+k)^3=2^3 or 9+k=2 k=7

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks guys :) but.. why is 8=2^3?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(9+k)^3+(127)^2=0+33 (9+k)^3+25=33 (9+k)^3=8 8=2^3 so (9+k)^3=2^3 or 9+k=2 k=
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.