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anonymous
 4 years ago
The angle of minimum deviation for a prism of refractive index 3/2 is equal to angle of prism. What is the angle of the prism? ( cos 41 = 0.75)
a) 31 degrees
b) 41 degrees
c) 62 degrees
d) 82 degrees
anonymous
 4 years ago
The angle of minimum deviation for a prism of refractive index 3/2 is equal to angle of prism. What is the angle of the prism? ( cos 41 = 0.75) a) 31 degrees b) 41 degrees c) 62 degrees d) 82 degrees

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\mu=\sin ((A+\delta)/2)/\sin(A/2)\] here delta = A The RHS becomes sin(A)/sin(A/2)=2cos(A/2)=3/2 cos(A/2)=0.75 A/2=41 A=82.
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