A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Under certain circumstances, the number of generations of "good" bacteria needed to increase the frequency of a particular gene from is
n=4.572 integral 1/((x^2)(1x)) dx
anonymous
 4 years ago
Under certain circumstances, the number of generations of "good" bacteria needed to increase the frequency of a particular gene from is n=4.572 integral 1/((x^2)(1x)) dx

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[n=4.572\int\limits_{0.1}^{0.6}1/(x^2(1x))dx\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0find n, rounded to the nearest whole

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int \frac{1}{x^2(1x)} dx\] Hmm I would like to try partial fraction \[\frac{1}{x^2(1+x)} = \frac{A}{1+x} + \frac{Bx +C}{x^2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0partial fraction been a long time... i think its the denominator your working on right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[1 = Ax^2 + Bx^2 + Bx + Cx + C \] Comparing coefficient C = 1; (A+B) = 0; (B+C) = 0 Now you can integrate it! :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Umm the Numerator \[\frac{1}{x^2(1+x)} = \frac{Ax^2 + Bx^2 + Bx + Cx + C}{x^2 (x+1)} = 1 = Ax^2 + Bx^2 + Bx + Cx + C\] Denominators cancel out.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{1}{x^2(1+x)} = \frac{Ax^2 + Bx^2 + Bx + Cx + C}{x^2 (x+1)} \implies 1 = Ax^2 + Bx^2 + Bx + Cx + C\] This version is much better

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0your 1/x^2(1x) becomes 1/x^2(1+x) typo?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh Crap, yeah typo but the concept is same and I also messed up my calculations but the concept remains the same. Instead of \[\frac{1}{x^2(1+x)} = \frac{A}{1+x} + \frac{Bx +C}{x^2}\] you will have to do \[\frac{1}{x^2(1x)} = \frac{A}{1x} + \frac{Bx +C}{x^2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so its gonna be 1=\[x^2(AB)+x(BC)+C\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0C= 1, (AB) = 0, (BC)=0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0my answer is 50 =) is that right?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.