why the internal energy is 0 in case of isolated system? I mean, how the dq and dw are both 0
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In an isolated system, dQ and dW are zero because there is no change in heat or work.
how no change in work...i can understand that dq is 0..but please explain that hoe dw is 0
given\[W=\delta E_k=1/2*m*(v_2^2-v_1^2)\]as there is no external force (heat, pressure, etc.) the average velocity of the atoms will not change (some might speed up or slow down as they hit each other, but the average stays the same).
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this is the best explanation i have got...thanks for mending my concept
It's what I do ;)
What you mean it say is the the change in energy is zero for an isolated system, and that heat and work must both appear at the boundary of a system, because by definition they measure flows of energy across the boundary.