## anonymous 4 years ago Why ln(i)=(1/2)*pi*i?

1. anonymous

The situation actually was $i^i=e^{i*lni}=e^{i(1/2)\pi*i}=e^{-(1/2)\pi}$

2. EarthCitizen

yh, use Euler's formula

3. EarthCitizen

$e ^{i}e ^{lni}$

4. anonymous

How does $e^{i \pi}=-1$ help here, or is there another part of the formula that I;m missing?

5. EarthCitizen

$lni=i \pi/2$

6. anonymous

OK, Thanks. Could you point me to an article with the proof?

7. EarthCitizen