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jhonyy9
 4 years ago
 for example :
(21) (21)
 +  +1 = 2
2 2
(31) (31)
 +  +1 =3
2 2
(51) (31)
 +  +1 = 2 +1 +1 =4
2 2
(51) (51)
 +  +1 = 2+2+1=5
2 2
can be this proven that is true for every natural numbers ?
jhonyy9
 4 years ago
 for example : (21) (21)  +  +1 = 2 2 2 (31) (31)  +  +1 =3 2 2 (51) (31)  +  +1 = 2 +1 +1 =4 2 2 (51) (51)  +  +1 = 2+2+1=5 2 2 can be this proven that is true for every natural numbers ?

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jhonyy9
 4 years ago
Best ResponseYou've already chosen the best response.0can be do it by induction ?

EscherichiaRinku
 4 years ago
Best ResponseYou've already chosen the best response.0The difficult part here is probably getting a general formula. Then proving it by induction shouldn't be hard.

hoblos
 4 years ago
Best ResponseYou've already chosen the best response.1(a1) (a1) 2a 2  +  +1 =  +1 = a1+1 =a 2 2 2

hoblos
 4 years ago
Best ResponseYou've already chosen the best response.1this is true for any natural number

jhonyy9
 4 years ago
Best ResponseYou've already chosen the best response.0,,hoblos" yes i see it but this need to be proven

jhonyy9
 4 years ago
Best ResponseYou've already chosen the best response.0so if we know that p and k are primes

jhonyy9
 4 years ago
Best ResponseYou've already chosen the best response.0 prove that for every n natural numbers grater or equal 2 exist one p and k numbers prim grater or equal 2 such that the below equation is true : (p1) (k1)  +  +1 = n 2 2

jhonyy9
 4 years ago
Best ResponseYou've already chosen the best response.0this was my previosly question

jhonyy9
 4 years ago
Best ResponseYou've already chosen the best response.0so than p=2a+1 and k=2b+1

hoblos
 4 years ago
Best ResponseYou've already chosen the best response.1actually there exist more than one p & k such that the equation is true!! for example: if n=4 you may take (p=5 k=3) or (p=7 k=1) but there is one condition that must be satisfied which is n=(p+k)/2

jhonyy9
 4 years ago
Best ResponseYou've already chosen the best response.0so but do you can prove it in one proning style ,method that is true for every natural numbers ?

jhonyy9
 4 years ago
Best ResponseYou've already chosen the best response.0sorry proving stayle ,method

hoblos
 4 years ago
Best ResponseYou've already chosen the best response.1well.. i have only this method for now for all natural numbers p & k , there exist n such that (p1) (k1)  +  +1 = n => (p+k)/2 1+1=n => n=(p+k)/2 2 2

jhonyy9
 4 years ago
Best ResponseYou've already chosen the best response.0not right because if you see the first sentence of this exercise there is that p and k are prims

hoblos
 4 years ago
Best ResponseYou've already chosen the best response.1they dont have to be primes try p=6 k=4 and you will get n=5 the exercise is also stating that we have only one p&k while we have more than one!!

jhonyy9
 4 years ago
Best ResponseYou've already chosen the best response.0but is indifferent from this exercise p and k are prims
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