Just imagine that this is a right triangle where d is the altitude. Find the values of a, b, c, d. About the Right Triangle Similarity.... |\ Given: a+b = 18 | \ a | \ | /\ 6| / \ | /d \ b | / \ | / \ |/_________\ c Please help me... Thanks

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Just imagine that this is a right triangle where d is the altitude. Find the values of a, b, c, d. About the Right Triangle Similarity.... |\ Given: a+b = 18 | \ a | \ | /\ 6| / \ | /d \ b | / \ | / \ |/_________\ c Please help me... Thanks

Mathematics
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1 Attachment
18^2-6^2=c^2 c=12sqrt2
what? I dont get it..

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Other answers:

there's the picture
Use the pythagorean theorem to get c
Then redraw all three triangles so they corresponding sides are in corresponding positions.
what do you mean?
do you know the Pythagorean Theorem?
yeah
Use it to find c
What did you get?
|dw:1327846316363:dw|
Use similar triangles to get the other parts.
how do i get it? I really dont know
The pythagorean theorem says the if you square the legs and add those numbers together, you will get the hypotenuse squared. do you know that?
i'm back
this is so hard
So if you look at the picture I posted, you will see that one leg is 6 and the hypotenuse is 18.
Do you understand that much?
yes
So find c by solving this: c^2+6^2 = 18^2
And tell me what you get.
16
324-36=288 sqrt288= 12sqrt2 so c is 12sqrt2
is it right?
|dw:1327847562955:dw|
ok
Do you know that right triangles have legs and a hypotenuse?
what about a?
yes
Look at the picture. Corresponding parts have equal ratios.so 6/a=18/6 Solve that for a
is it 2?
|dw:1327847690198:dw|
Yes. Now find b. You know that a+b=18
b=16
Now find d using your choice of similar triangles of the pythagorean theorem.
d= 3sqrt2
Using the small triangle:\[a^2+d^2=6^2\] \[2^2+d^2=36\] \[d^2=32\] \[d=\sqrt{16(2)}\] \[d=4\sqrt{2}\]
wow :) thanks can you please help me with one more problem.. i'll just post the image here
I'll try
1 Attachment
Well, there aren't any numbers given so if you want numerical values there has to be more information.
ok, so what do we do
the answer might not be in numerical value
Well we could use the pythagorean theorem and leave the answers in terms of x, y , and z
ok
What I really think is that if you would look carefully, you would find sosme values
how? i'm not good at this..
read the directions. Perhaps it says something at the beginning of the problem set.
nope there isnt any..
What class are you taking?
g
geometry
It helps me know the level of understanding you are supposed to exhibit.
So z^2=y^2+(x+1)^2 z=sqrt(y^2+(x+1)^2)
ok
(x+1)^2+y^2=z^2 (x+1)^2=z^2-y^2 x+1=sqrt(z^2-y^2) x=sqrt(z^2-y^2)-1
x^2+y^2=(x+2)^2 y^2=(x+2)^2-x^2 y=sqrt[(x+2)^2-x^2]
Those will have to do until you find some numerical values.
ok... thanks :)
yw

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