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anonymous

  • 4 years ago

Just imagine that this is a right triangle where d is the altitude. Find the values of a, b, c, d. About the Right Triangle Similarity.... |\ Given: a+b = 18 | \ a | \ | /\ 6| / \ | /d \ b | / \ | / \ |/_________\ c Please help me... Thanks

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  1. anonymous
    • 4 years ago
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  2. Mertsj
    • 4 years ago
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    18^2-6^2=c^2 c=12sqrt2

  3. anonymous
    • 4 years ago
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    what? I dont get it..

  4. anonymous
    • 4 years ago
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    there's the picture

  5. Mertsj
    • 4 years ago
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    Use the pythagorean theorem to get c

  6. Mertsj
    • 4 years ago
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    Then redraw all three triangles so they corresponding sides are in corresponding positions.

  7. anonymous
    • 4 years ago
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    what do you mean?

  8. Mertsj
    • 4 years ago
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    do you know the Pythagorean Theorem?

  9. anonymous
    • 4 years ago
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    yeah

  10. Mertsj
    • 4 years ago
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    Use it to find c

  11. Mertsj
    • 4 years ago
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    What did you get?

  12. Mertsj
    • 4 years ago
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    |dw:1327846316363:dw|

  13. Mertsj
    • 4 years ago
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    Use similar triangles to get the other parts.

  14. anonymous
    • 4 years ago
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    how do i get it? I really dont know

  15. Mertsj
    • 4 years ago
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    The pythagorean theorem says the if you square the legs and add those numbers together, you will get the hypotenuse squared. do you know that?

  16. anonymous
    • 4 years ago
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    i'm back

  17. anonymous
    • 4 years ago
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    this is so hard

  18. Mertsj
    • 4 years ago
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    So if you look at the picture I posted, you will see that one leg is 6 and the hypotenuse is 18.

  19. Mertsj
    • 4 years ago
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    Do you understand that much?

  20. anonymous
    • 4 years ago
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    yes

  21. Mertsj
    • 4 years ago
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    So find c by solving this: c^2+6^2 = 18^2

  22. Mertsj
    • 4 years ago
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    And tell me what you get.

  23. anonymous
    • 4 years ago
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    16

  24. Mertsj
    • 4 years ago
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    324-36=288 sqrt288= 12sqrt2 so c is 12sqrt2

  25. anonymous
    • 4 years ago
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    is it right?

  26. Mertsj
    • 4 years ago
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    |dw:1327847562955:dw|

  27. anonymous
    • 4 years ago
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    ok

  28. Mertsj
    • 4 years ago
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    Do you know that right triangles have legs and a hypotenuse?

  29. anonymous
    • 4 years ago
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    what about a?

  30. anonymous
    • 4 years ago
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    yes

  31. Mertsj
    • 4 years ago
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    Look at the picture. Corresponding parts have equal ratios.so 6/a=18/6 Solve that for a

  32. anonymous
    • 4 years ago
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    is it 2?

  33. Mertsj
    • 4 years ago
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    |dw:1327847690198:dw|

  34. Mertsj
    • 4 years ago
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    Yes. Now find b. You know that a+b=18

  35. anonymous
    • 4 years ago
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    b=16

  36. Mertsj
    • 4 years ago
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    Now find d using your choice of similar triangles of the pythagorean theorem.

  37. anonymous
    • 4 years ago
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    d= 3sqrt2

  38. Mertsj
    • 4 years ago
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    Using the small triangle:\[a^2+d^2=6^2\] \[2^2+d^2=36\] \[d^2=32\] \[d=\sqrt{16(2)}\] \[d=4\sqrt{2}\]

  39. anonymous
    • 4 years ago
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    wow :) thanks can you please help me with one more problem.. i'll just post the image here

  40. Mertsj
    • 4 years ago
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    I'll try

  41. anonymous
    • 4 years ago
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  42. Mertsj
    • 4 years ago
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    Well, there aren't any numbers given so if you want numerical values there has to be more information.

  43. anonymous
    • 4 years ago
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    ok, so what do we do

  44. anonymous
    • 4 years ago
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    the answer might not be in numerical value

  45. Mertsj
    • 4 years ago
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    Well we could use the pythagorean theorem and leave the answers in terms of x, y , and z

  46. anonymous
    • 4 years ago
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    ok

  47. Mertsj
    • 4 years ago
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    What I really think is that if you would look carefully, you would find sosme values

  48. anonymous
    • 4 years ago
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    how? i'm not good at this..

  49. Mertsj
    • 4 years ago
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    read the directions. Perhaps it says something at the beginning of the problem set.

  50. anonymous
    • 4 years ago
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    nope there isnt any..

  51. Mertsj
    • 4 years ago
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    What class are you taking?

  52. anonymous
    • 4 years ago
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    g

  53. anonymous
    • 4 years ago
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    geometry

  54. Mertsj
    • 4 years ago
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    It helps me know the level of understanding you are supposed to exhibit.

  55. Mertsj
    • 4 years ago
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    So z^2=y^2+(x+1)^2 z=sqrt(y^2+(x+1)^2)

  56. anonymous
    • 4 years ago
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    ok

  57. Mertsj
    • 4 years ago
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    (x+1)^2+y^2=z^2 (x+1)^2=z^2-y^2 x+1=sqrt(z^2-y^2) x=sqrt(z^2-y^2)-1

  58. Mertsj
    • 4 years ago
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    x^2+y^2=(x+2)^2 y^2=(x+2)^2-x^2 y=sqrt[(x+2)^2-x^2]

  59. Mertsj
    • 4 years ago
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    Those will have to do until you find some numerical values.

  60. anonymous
    • 4 years ago
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    ok... thanks :)

  61. Mertsj
    • 4 years ago
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    yw

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