anonymous
  • anonymous
Just imagine that this is a right triangle where d is the altitude. Find the values of a, b, c, d. About the Right Triangle Similarity.... |\ Given: a+b = 18 | \ a | \ | /\ 6| / \ | /d \ b | / \ | / \ |/_________\ c Please help me... Thanks
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
1 Attachment
Mertsj
  • Mertsj
18^2-6^2=c^2 c=12sqrt2
anonymous
  • anonymous
what? I dont get it..

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anonymous
  • anonymous
there's the picture
Mertsj
  • Mertsj
Use the pythagorean theorem to get c
Mertsj
  • Mertsj
Then redraw all three triangles so they corresponding sides are in corresponding positions.
anonymous
  • anonymous
what do you mean?
Mertsj
  • Mertsj
do you know the Pythagorean Theorem?
anonymous
  • anonymous
yeah
Mertsj
  • Mertsj
Use it to find c
Mertsj
  • Mertsj
What did you get?
Mertsj
  • Mertsj
|dw:1327846316363:dw|
Mertsj
  • Mertsj
Use similar triangles to get the other parts.
anonymous
  • anonymous
how do i get it? I really dont know
Mertsj
  • Mertsj
The pythagorean theorem says the if you square the legs and add those numbers together, you will get the hypotenuse squared. do you know that?
anonymous
  • anonymous
i'm back
anonymous
  • anonymous
this is so hard
Mertsj
  • Mertsj
So if you look at the picture I posted, you will see that one leg is 6 and the hypotenuse is 18.
Mertsj
  • Mertsj
Do you understand that much?
anonymous
  • anonymous
yes
Mertsj
  • Mertsj
So find c by solving this: c^2+6^2 = 18^2
Mertsj
  • Mertsj
And tell me what you get.
anonymous
  • anonymous
16
Mertsj
  • Mertsj
324-36=288 sqrt288= 12sqrt2 so c is 12sqrt2
anonymous
  • anonymous
is it right?
Mertsj
  • Mertsj
|dw:1327847562955:dw|
anonymous
  • anonymous
ok
Mertsj
  • Mertsj
Do you know that right triangles have legs and a hypotenuse?
anonymous
  • anonymous
what about a?
anonymous
  • anonymous
yes
Mertsj
  • Mertsj
Look at the picture. Corresponding parts have equal ratios.so 6/a=18/6 Solve that for a
anonymous
  • anonymous
is it 2?
Mertsj
  • Mertsj
|dw:1327847690198:dw|
Mertsj
  • Mertsj
Yes. Now find b. You know that a+b=18
anonymous
  • anonymous
b=16
Mertsj
  • Mertsj
Now find d using your choice of similar triangles of the pythagorean theorem.
anonymous
  • anonymous
d= 3sqrt2
Mertsj
  • Mertsj
Using the small triangle:\[a^2+d^2=6^2\] \[2^2+d^2=36\] \[d^2=32\] \[d=\sqrt{16(2)}\] \[d=4\sqrt{2}\]
anonymous
  • anonymous
wow :) thanks can you please help me with one more problem.. i'll just post the image here
Mertsj
  • Mertsj
I'll try
anonymous
  • anonymous
1 Attachment
Mertsj
  • Mertsj
Well, there aren't any numbers given so if you want numerical values there has to be more information.
anonymous
  • anonymous
ok, so what do we do
anonymous
  • anonymous
the answer might not be in numerical value
Mertsj
  • Mertsj
Well we could use the pythagorean theorem and leave the answers in terms of x, y , and z
anonymous
  • anonymous
ok
Mertsj
  • Mertsj
What I really think is that if you would look carefully, you would find sosme values
anonymous
  • anonymous
how? i'm not good at this..
Mertsj
  • Mertsj
read the directions. Perhaps it says something at the beginning of the problem set.
anonymous
  • anonymous
nope there isnt any..
Mertsj
  • Mertsj
What class are you taking?
anonymous
  • anonymous
g
anonymous
  • anonymous
geometry
Mertsj
  • Mertsj
It helps me know the level of understanding you are supposed to exhibit.
Mertsj
  • Mertsj
So z^2=y^2+(x+1)^2 z=sqrt(y^2+(x+1)^2)
anonymous
  • anonymous
ok
Mertsj
  • Mertsj
(x+1)^2+y^2=z^2 (x+1)^2=z^2-y^2 x+1=sqrt(z^2-y^2) x=sqrt(z^2-y^2)-1
Mertsj
  • Mertsj
x^2+y^2=(x+2)^2 y^2=(x+2)^2-x^2 y=sqrt[(x+2)^2-x^2]
Mertsj
  • Mertsj
Those will have to do until you find some numerical values.
anonymous
  • anonymous
ok... thanks :)
Mertsj
  • Mertsj
yw

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