anonymous
  • anonymous
A positive integer is picked randomly from 41 to 50, inclusive. What is the probability that it is divisible by either 3 or 5? Write your answer as a simplified fraction
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
again we count only ten numbers to count 41,42,43,44,45,46,47,48,49,50 then we count the ones divisible by 3, and the ones divisible by 5
anonymous
  • anonymous
All integers are divisible by 3 or 5. What I think you meant is divisible by 3 or 5 without a remainder right?
anonymous
  • anonymous
divisible by 3: 42,45,48 divisible by 5: 45,50 just make sure not to count 45 twice (the whole point of this problem) so the set is {42,45,48,50} i.e 4 out of the 10

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anonymous
  • anonymous
ya commodoc that is implied
anonymous
  • anonymous
so these events are not mutually exclusive and we apply the concept of union ?
anonymous
  • anonymous
well they are not mutually exclusive that is for sure, since 45 is both divisible by 3 and by 5
anonymous
  • anonymous
i am not sure what you mean by "concept of union" you would take the union of the two events in any case, whether they are mutually exclusive or not
anonymous
  • anonymous
but what is the concept of union and intersection in probability
anonymous
  • anonymous
commdoc u can also try
anonymous
  • anonymous
unions and intersections are set operations. so for the example above if A is "divisible by 3" and B is "divisible by 5" then \[A=\{42,45,48\}\] \[B=\{45,50\}\] \[A\cup B=\{42,45,48,50\}\] \[A\cap B=\{45\}\]
anonymous
  • anonymous
and you can see that \[P(A\cup B)=P(A)+P(B)-P(A\cap B)\]
anonymous
  • anonymous
so in union ever item is considered and in intersection only the common item is taken
anonymous
  • anonymous
hey commdoc u r doing which subject in ur ph.d?
anonymous
  • anonymous
ee with concentration in communications specifically coding theory
anonymous
  • anonymous
Hey satellite how do you get the drawings in the blog?

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