anonymous
  • anonymous
A positive integer is picked randomly from 61 to 70, inclusive. What is the probability that it is prime?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
pls explain the concept of prime no
anonymous
  • anonymous
The numbers from 61 to 70 are: 61, 62, 63, 64, 65, 66, 67, 68, 69, 70 Prime numbers: 61, 63, 67, 69
anonymous
  • anonymous
do you know what "prime number " means?

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anonymous
  • anonymous
i m confused
hoblos
  • hoblos
the prime numbers are 61 & 67 only
anonymous
  • anonymous
lol prime is not odd!
anonymous
  • anonymous
prime means only divisors are 1 and itself, a whole number that you cannot factor
hoblos
  • hoblos
so the probability is 2/10 = 1/5
anonymous
  • anonymous
we can try the numbers one by one and check
anonymous
  • anonymous
okay,pratu u were mistaken
anonymous
  • anonymous
61, 62, 63, 64, 65, 66, 67, 68, 69, 70 61 is prime because it is not the product of any two numbers. think about the multiplication table. 61 does not appear as an entry there
anonymous
  • anonymous
62 is even, so it is divisible by 2, not prime. and neither are 64,66,68,70 for the same reason
anonymous
  • anonymous
63 is divisible by 3 because \[63=3\times 21\]
anonymous
  • anonymous
why did u take such a big no?
anonymous
  • anonymous
65 is obviously divisible by 5 67 is prime and finally 69 is divisible by 3
anonymous
  • anonymous
I think a better question is how do you know if a number is a prime. We know that all even numbers are not prime. But which of the odd ones are prime. I guess the question is how would you calculate if a number is or is not prime? For example, 3335679 ?
anonymous
  • anonymous
true
anonymous
  • anonymous
Can this only be done by brute force. i.e. take each integer and start dividing by the smaller integers and then keep going until you reach an answer without a remainder? We need a mathematician.
anonymous
  • anonymous
well sorry i m a lost in maths
anonymous
  • anonymous
Yeah, I made a mistake and had some internet problem in the middle so couldn't reply. The others are right though.
hoblos
  • hoblos
some notes that may help: if the number is even then it is divisible by 2 if the sum of digits of the number is divisible by 3 then the whole number is divisible by 3 if the number ends with 0 or 5 then it is divisible by 5 out of these cases you have to try dividing by PRIME numbers until you reach an answer without a remainder

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