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anonymous

  • 4 years ago

find a vector equation and parametric equations for the line through point (0,14,-10) and parallel to the line x=-1+2T, y=6-3T, Z=3+9T

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  1. amistre64
    • 4 years ago
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    parallel have same vector parts; just different point parts

  2. amistre64
    • 4 years ago
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    x = -1+2t y = 6-3t z = 3+9t strip off the old point (-1,6,3) x = Px+2t y = Py-3t z = Pz+9t and add in the new point (0,14,-10) x = 0+2t y = 14-3t z = -10+9t and we get the parametric

  3. amistre64
    • 4 years ago
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    what a vector equation look like? is the that v = i+j+k stuff?

  4. anonymous
    • 4 years ago
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    what does the 2T, -3T and 9T represent?

  5. anonymous
    • 4 years ago
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    yes it is

  6. amistre64
    • 4 years ago
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    the vector <2,-3,9> strecthed to any scalar "t"

  7. amistre64
    • 4 years ago
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    to form a line; its just a vector attached to a pointand strecthched to hit all point on the line

  8. amistre64
    • 4 years ago
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    v = t(2i -3j +9) maybe?

  9. amistre64
    • 4 years ago
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    i got no idea how your text formats a vector equation, but its pretty basic from that i believe

  10. anonymous
    • 4 years ago
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    okay how would i do it if it was perpendicular instead of parallel?

  11. amistre64
    • 4 years ago
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    the perp vector has to dot with the original vector and get 0

  12. amistre64
    • 4 years ago
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    2,-3,9 a, b, c ------- 2a-3b+9c = 0

  13. anonymous
    • 4 years ago
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    okay still kinda confused, i'll ask another question on it hang on

  14. amistre64
    • 4 years ago
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    there are infinelty many perp vector to a line; they form a plane all around it

  15. amistre64
    • 4 years ago
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    |dw:1327851858959:dw|

  16. anonymous
    • 4 years ago
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    okay that makes sense, can you look at my new question please?

  17. amistre64
    • 4 years ago
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    sure

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