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anonymous
 4 years ago
If tangents QR, PR, and PQ are drawn respectively at A, B and C to the circle circumscribing an acute angled triangle triangle ABC so as to form another triangle PQR, then find the alternative equivalent to angle RPQ.
a) Angle BAC
b) 0.5( 180 degrees  angle BAC)
c) 180 degrees  angle BAC
d) (180 degrees  2 times angle BAC)
anonymous
 4 years ago
If tangents QR, PR, and PQ are drawn respectively at A, B and C to the circle circumscribing an acute angled triangle triangle ABC so as to form another triangle PQR, then find the alternative equivalent to angle RPQ. a) Angle BAC b) 0.5( 180 degrees  angle BAC) c) 180 degrees  angle BAC d) (180 degrees  2 times angle BAC)

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AravindG
 4 years ago
Best ResponseYou've already chosen the best response.2a fig would be helpful

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But figure is not given.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Just try it out. I believe figure is not that difficult.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Someone reply me plzzzzzzzzzzzzzz.

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.2srry i gotta go help ya latr

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0option d is correct...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay. As ur wish. But others p[lzzzzzzzzzz try it out.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am assuming that vertex P is opposite of A, i.e. it is created by tangents to B and C .. ( normal convention) .. Now when you complete the triangle PQR , concentrate on quadilateral OBCP ... here angle OBP = OCP = 90 and hence angle BOC = 180  P. Now segment BC for the circle also suspends angle A on the circumference which would be half of what the segment suspends on the center (property of circle) .. hence (180p)/2 = A ... hence p = 180  2A

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0O is the center of the circle

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Brother, one physics doubt. Help please.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0http://openstudy.com/study#/updates/4f25694ce4b0a2a9c266e802
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