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Aadarsh
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If tangents QR, PR, and PQ are drawn respectively at A, B and C to the circle circumscribing an acute angled triangle triangle ABC so as to form another triangle PQR, then find the alternative equivalent to angle RPQ.
a) Angle BAC
b) 0.5( 180 degrees  angle BAC)
c) 180 degrees  angle BAC
d) (180 degrees  2 times angle BAC)
 2 years ago
 2 years ago
Aadarsh Group Title
If tangents QR, PR, and PQ are drawn respectively at A, B and C to the circle circumscribing an acute angled triangle triangle ABC so as to form another triangle PQR, then find the alternative equivalent to angle RPQ. a) Angle BAC b) 0.5( 180 degrees  angle BAC) c) 180 degrees  angle BAC d) (180 degrees  2 times angle BAC)
 2 years ago
 2 years ago

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AravindG Group TitleBest ResponseYou've already chosen the best response.2
a fig would be helpful
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
But figure is not given.
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
Just try it out. I believe figure is not that difficult.
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
Someone reply me plzzzzzzzzzzzzzz.
 2 years ago

AravindG Group TitleBest ResponseYou've already chosen the best response.2
srry i gotta go help ya latr
 2 years ago

shaan_iitk Group TitleBest ResponseYou've already chosen the best response.0
option d is correct...
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
Okay. As ur wish. But others p[lzzzzzzzzzz try it out.
 2 years ago

shaan_iitk Group TitleBest ResponseYou've already chosen the best response.0
I am assuming that vertex P is opposite of A, i.e. it is created by tangents to B and C .. ( normal convention) .. Now when you complete the triangle PQR , concentrate on quadilateral OBCP ... here angle OBP = OCP = 90 and hence angle BOC = 180  P. Now segment BC for the circle also suspends angle A on the circumference which would be half of what the segment suspends on the center (property of circle) .. hence (180p)/2 = A ... hence p = 180  2A
 2 years ago

shaan_iitk Group TitleBest ResponseYou've already chosen the best response.0
O is the center of the circle
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
Thanks a lot
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
Brother, one physics doubt. Help please.
 2 years ago

Aadarsh Group TitleBest ResponseYou've already chosen the best response.0
http://openstudy.com/study#/updates/4f25694ce4b0a2a9c266e802
 2 years ago
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