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anonymous
 4 years ago
find the equation of the plane through point (2,8,10) and perpendicular to line x=1+T, y=2T, z=43T
anonymous
 4 years ago
find the equation of the plane through point (2,8,10) and perpendicular to line x=1+T, y=2T, z=43T

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is the answer: x+2y3z=16?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1our perp line gives us our normal to the plane so strip out the vector in it

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1<1,2,3> now apply this to any random point (x,y,z)  (2,8,10) 1(x2) +2(y8) 3(z10) = 0 x+2 +2y 16 3z +30 = 0 x +2y 3z +16 = 0 x +2y 3z = 16 dbl chk the math to be sure, i tend to forget how to add and subtract lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yay i'm figuring out how to do this!!

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1pretty soon youll be like; I cant believe I didnt know this stuff !!! :)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1i figure in a few weeks we will be going over this in calc 3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay so for the plane through the origin and points (x,y,z) and (a,b,c,) i would do do (a,b,c)x(x,y,z) to find the normal right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and then use the normal to write an equation

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1yes, since the origin is one of our points; the other 2 points are also the vectors; so cross them and get the normal

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1then use the normal attached to any of the 3 points (0,0,0) being the most useful id assume

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0will my answer be a dot product?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1the cross of 2 vectors is a vector

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0of the normal and (x,y,z)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1your answer will be a dot product of the normal and every vector in the plane: <x0, y0, z0> would define all vector in the plane

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay awesome thats what i got!
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