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anonymous
 4 years ago
which of the following is an odd function?
a. f(x)= xcosx
b.f(x)= xsinx
c.f(x)= e ^cosx
d.f(x)=sin^2x
anonymous
 4 years ago
which of the following is an odd function? a. f(x)= xcosx b.f(x)= xsinx c.f(x)= e ^cosx d.f(x)=sin^2x

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JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0Test and see. What's the definition of an odd function?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0my answer again is letter c i dont know y.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if a or b my answer the wiki is correct

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0By definition, a function f is odd if \[ f(x) = f(x) \] The function in c is not odd ...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you need to check to see if \[f(x)=f(x)\] for even or if \[f(x)=f(x)\] for odd and there is no shame in trying it with numbers if the x's get confusing

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it won't be a proof, but it will give you an idea of what is going on. then you can do it with a variable

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0...because \[ \cos(x) = \cos(x) \] hence \[ e^{\cos(x) } = e^{\cos(x)} \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0odd x odd = even even x odd= odd even x even= even

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ic all your answer is correct but a or b are the same right? i only need to choose 1 letter and it is letter D

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0No. The function is D is not odd, because \[ \sin^2(x) = (\sin(x))^2 = (\sin x)^2 = \sin^2 x \]

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0hence the function in D and C are both even functions: \[ f(x) = f(x) \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how could i know a and b are odd? i feel sinx and cosx are the same

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0OMG its LETTER B because cos x is an even function

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0No. Try and work it out by explicitly evaluating expressions.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Geometrically, the graph of an odd function has rotational symmetry with respect to the origin, meaning that its graph remains unchanged after rotation of 180 degrees about the origin. Examples of odd functions are x, x3, sin(x), sinh(x), and erf(x).

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0Yes. But stop avoiding doing the calculation. Take each of the functions in turn and evaluate f(x). See if it equal to f(x) or not. If it is, then f(x) is odd. That is how you answer this question.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0f(x) = sinx is odd function so f(x) = xcosx

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0f(x) = x.cos(x) is an odd function yes. Why? Because f(x) = (x).cos(x) = x.cos(x) , because cos(x) = cos(x) = f(x)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its like f(x) = f(x) thank your mister james

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.0By definition, a function f(x) is odd if f(x) = f(x)
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