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heena
Group Title
ok they had given pendulum done 100 oscillation its amplitude reduced to 1/3 of initial value. what will be its amplitude if it completes 200 oscillation
 2 years ago
 2 years ago
heena Group Title
ok they had given pendulum done 100 oscillation its amplitude reduced to 1/3 of initial value. what will be its amplitude if it completes 200 oscillation
 2 years ago
 2 years ago

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JamesJ Group TitleBest ResponseYou've already chosen the best response.0
100 oscillations in what time period?
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
dont solve just tell me ur vies dat how will u suppose to handle this ques plz plz but dont solve
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
*view they didnt give time period so we can assume it constant??
 2 years ago

JamesJ Group TitleBest ResponseYou've already chosen the best response.0
I still don't understand the question. Is it this: "In a given time period a pendulum completes 100 oscillations. "Then the pendulum has its amplitude decreased by 1/3 and it completes in the same time period 200 oscillations." If so, what's the question here.
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
no they didnt said anything abu time period even i m asking can we assume it constant
 2 years ago

JamesJ Group TitleBest ResponseYou've already chosen the best response.0
What is true about a pendulum is that if you increase the angle of maximum oscillation more than about 10 degrees, the period of the pendulum increases. The reason for that is in calculating the standard period of pendulum, we use a small angle approximation \[ \sin\theta \approx \theta \] which only holds for small angles \( \theta \). The wikipedia article has good animation of what happens when \( \theta \) gets large and there you can see the period increases. http://en.wikipedia.org/wiki/Pendulum#Period_of_oscillation This would explain the effect described in this set up.
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
but james my ques how i m gonna solve it ? any hint or idea even i m trying hit and try but u can tell ur one too that it might like dis?
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
u guys have any idea?
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
it is saying that when pendulum completes its 100 oscilation its amplitude reduced to 1/3 of its inital means 2/3 is remain of apmlitude i guess and then they are asking if it completes 200 oscilation than what will be the value of amplitude
 2 years ago

hosein Group TitleBest ResponseYou've already chosen the best response.1
i think amplitude decrease
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
i need a value too.. :P
 2 years ago

JamesJ Group TitleBest ResponseYou've already chosen the best response.0
Oh, I see. Precisely what is the amplitude, in angular terms. Use the first couple of terms of this expansion:
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
god.. u r kidding james by showin me dat short formula rit ...
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
i thinks in that i m not getting they are squaring or wat?? inside the bracket?
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.0
hello. i am back.
 2 years ago

hosein Group TitleBest ResponseYou've already chosen the best response.1
with 100 oscillation amp 1/3 decrease so with 200 oscillation again decrease 1/3 im not sure
 2 years ago

JamesJ Group TitleBest ResponseYou've already chosen the best response.0
You know that T decreases by a factor of a 1/2. Use that formula to find what value of theta_0 will make that happen.
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.0
may i help here? May i could do something?
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
yea solve diss ques
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.0
ok wait. let me analyze.
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
i wasted 15mins in this ques yar
 2 years ago

hosein Group TitleBest ResponseYou've already chosen the best response.1
james formula is correct?
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
yea but unable to aplly a i nvr heard abu dat one
 2 years ago

hosein Group TitleBest ResponseYou've already chosen the best response.1
james formula abu period of oscillation,not amplitude
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.0
now what i understand. BUT THIS QUESTION LOOKS INCOMPLETE. look here first calculate time period using T=1/f T=1/100 T=0.01sec
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
guys i need the ans 1/9 nw think ow can we get
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
f=? y u put ocilation??
 2 years ago

hosein Group TitleBest ResponseYou've already chosen the best response.1
idont understand u'r sentence?
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
i mean the ans of this ques is 1/9 now just hit and try to get this ans
 2 years ago

hosein Group TitleBest ResponseYou've already chosen the best response.1
how can you got it?
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
no i dont got dat i had ans key :) and my ans is not matching dats why i ask for help..
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.0
now use the displacement equation, y=Asinwt where w is the frequency. y=(1/3) sin(100*0.01) y=(1/3)(0.0174) y=0.005m now use this displacement as, 0.005=Asin(200*0.01) 0.005=A(0.0348) A=0.143 :( is this wrong?
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.0
there is no other way to do it. so it tried my best. and result is before you. :((
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
i want to cry.. :"( )............ )............................ god if this kind of ques coming on exam i m gonna dead
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.0
what is exact answer?
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.0
i am sure it is right.
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
1/9 i meantion it too
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.0
1/9 is equals to 0.1. so it is right. may be.
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
yes u r rit u got it congo.........
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.0
congo?
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
but in ur equation asinwt here t is time not time period
 2 years ago

JamesJ Group TitleBest ResponseYou've already chosen the best response.0
Heena. Let's try this one last time. Write out the complete question in your best English.
 2 years ago

hosein Group TitleBest ResponseYou've already chosen the best response.1
ithink shayan answer is wrong.
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
when an osicllator completes 100 oscilation then its amplitude reduced to 1/3 of its initial value of amplitude.what will be its amplitude if an osicllator completes 200 oscilation
 2 years ago

JamesJ Group TitleBest ResponseYou've already chosen the best response.0
This question is still very ambiguous. It means either * The time periods for the 100 and 200 oscillations are different and just a distraction. The amplitude is 3rd of what it is and that's the end of it. * We're talking about a pendulum and the period of oscillation changes. In which case we need to use the formula I wrote above * Something else.
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.0
i know. when i said it is true. it may be wrong. i just tried. although i am an electronics engineer not a theoritical physicist.
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
guys had a idea leave it even i already wasted 30 mins in this ques better to leave this i ll ask my lecturer dont worry
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.0
yeah, good idea.
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
thnQ for being here for help .. i always gave good ideas u knw gyan guru :P
 2 years ago

hosein Group TitleBest ResponseYou've already chosen the best response.1
why gave me medal i can't solve your ques
 2 years ago

Shayaan_Mustafa Group TitleBest ResponseYou've already chosen the best response.0
well i am going. good luck every one. take care.
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
hey medal is not for only those who solve the ques but its for those too who atleast tries to solve it ok
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
and i think u deserve as u given ur precious time to had a luk a my ques and tries it to solve as a help thnk you so much
 2 years ago

hosein Group TitleBest ResponseYou've already chosen the best response.1
this medal have not a value,i think however thanks for your attention sorry my english not well
 2 years ago

heena Group TitleBest ResponseYou've already chosen the best response.2
np i apreciate everyones work they did for helping others dats the main moto to give medals atleast people help others for medals.. and dnt think u dont solve dis medal is for ur work out in this ques ok..
 2 years ago
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