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anonymous
 4 years ago
pls help me..
anonymous
 4 years ago
pls help me..

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ash2326
 4 years ago
Best ResponseYou've already chosen the best response.2post your question, We'll try to help

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Are you trying to simplify the equation?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What are you trying to do here? Are x and y independent variables and a and b constants?

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.2Zhenecca I think the first term should be (9x^2y6xy+4y^3) it should not be 6xy2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(9x^2y6xy2+4y^3)/(x^2+2bxax2ab)÷((bx+2b^2)/(3x^239x+2xy2ay)*(27x^3+8y^3)/(bx^24b^3))

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.2as the function is very long, I'll try to simplify each term one by one

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.2We'll have in the numerator \[ (9x^2y6xy^2+4y^3)(3x^239x+2xy2ay)(bx^24b^3)\] in the denominator we'll have \[(x^2+2bxax2ab)(bx+2b^2)(27x^3+8y^3)\] now the numerator can be written as \[y(9x^26xy+4y^2)(3x^239x+2xy2ay) b(x^24b^2)\] denominator can be written as \[(x^2+2bxax2ab) b(x+2b^2)(3x+8y)(9x^26xy+4y^2)\]

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.2now canceling common terms from numerator and denominator numerator will be \[y(3x^239x+2xy2ay)b(x2b)\] and denominator will be \[(9x^2+2bxax2ab)b(3x+8y)\] so we get finally \[\frac{y(3x^239x+2xy2ay)(x2b)}{(9x^2+2bxax2ab)(3x+8y)}\]
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