anonymous
  • anonymous
pls help me..
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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ash2326
  • ash2326
post your question, We'll try to help
anonymous
  • anonymous
Are you trying to simplify the equation?
anonymous
  • anonymous
What are you trying to do here? Are x and y independent variables and a and b constants?

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ash2326
  • ash2326
Zhenecca I think the first term should be (9x^2y-6xy+4y^3) it should not be -6xy2
ash2326
  • ash2326
just check and tell
anonymous
  • anonymous
(9x^2y-6xy2+4y^3)/(x^2+2bx-ax-2ab)รท((bx+2b^2)/(3x^2-39x+2xy-2ay)*(27x^3+8y^3)/(bx^2-4b^3))
ash2326
  • ash2326
as the function is very long, I'll try to simplify each term one by one
anonymous
  • anonymous
its a fraction
ash2326
  • ash2326
We'll have in the numerator \[ (9x^2y-6xy^2+4y^3)(3x^2-39x+2xy-2ay)(bx^2-4b^3)\] in the denominator we'll have \[(x^2+2bx-ax-2ab)(bx+2b^2)(27x^3+8y^3)\] now the numerator can be written as \[y(9x^2-6xy+4y^2)(3x^2-39x+2xy-2ay) b(x^2-4b^2)\] denominator can be written as \[(x^2+2bx-ax-2ab) b(x+2b^2)(3x+8y)(9x^2-6xy+4y^2)\]
ash2326
  • ash2326
now canceling common terms from numerator and denominator numerator will be \[y(3x^2-39x+2xy-2ay)b(x-2b)\] and denominator will be \[(9x^2+2bx-ax-2ab)b(3x+8y)\] so we get finally \[\frac{y(3x^2-39x+2xy-2ay)(x-2b)}{(9x^2+2bx-ax-2ab)(3x+8y)}\]

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