A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 3 years ago
Let vectora=4i+3jalphak, vector b=2i+alphaj+k and vectorc=5ij+alphak, where alpha is a real number. Show that the vector c is not in the space spanned by vectors a and b. Pls help
 3 years ago
Let vectora=4i+3jalphak, vector b=2i+alphaj+k and vectorc=5ij+alphak, where alpha is a real number. Show that the vector c is not in the space spanned by vectors a and b. Pls help

This Question is Closed

JamesJ
 3 years ago
Best ResponseYou've already chosen the best response.2c is not in the span of a and b, if and only if the three vectors a,b,c are linearly independent. That means that the system of coefficients of the three vectors has nonzero determinant. So one way to show the result of the question is to show that the matrix 4 3 a 2 a 1 5 1 a has nonzero determinant.

atjari
 3 years ago
Best ResponseYou've already chosen the best response.0since alpha is unknown v cn't v shw that it has non zero determinant. isnt t?

atjari
 3 years ago
Best ResponseYou've already chosen the best response.0for 2 values of alpha the matrix becoes zero. then hw do v shw?

JamesJ
 3 years ago
Best ResponseYou've already chosen the best response.2Yes, you're exactly right. For two values of a, the determinant IS zero and hence the vector c DOES lie in the span of the vectors a and b. So the question as written is not exactly correct.

atjari
 3 years ago
Best ResponseYou've already chosen the best response.0if I solve c=pa+qb i get alpha as an imaginary number. so cn v say that "since alpha is given as real number bt v get here alpha as an imaginary number. so c is nt in the spce spand by a nd b."

JamesJ
 3 years ago
Best ResponseYou've already chosen the best response.2It's a brutal calculation, but if \[ \alpha = \frac{1}{9} (4 \pm \sqrt{115} ) \] then there are real numbers p and q such that c = pa + qb. For example, if alpha = (1/9) ( 4 + sqrt(115)), then \[ p = \frac{53  2\sqrt{115}}{2(\sqrt{115}22)}, q = \frac{\sqrt{115} 4}{2(\sqrt{115}22}\]

atjari
 3 years ago
Best ResponseYou've already chosen the best response.0how do u get this value for alpha? I get alpha as +/sqrt7+2

JamesJ
 3 years ago
Best ResponseYou've already chosen the best response.2the determinant of the matrix written above is \[ 9\alpha^2  8\alpha + 11 \] That expression is zero, when \( \alpha \) is \[ \alpha = \frac{4 \pm \sqrt{115}}{9} \]

atjari
 3 years ago
Best ResponseYou've already chosen the best response.0then hw do v shw that it is nt in the space?

JamesJ
 3 years ago
Best ResponseYou've already chosen the best response.2As I noted above, the question as written is wrong. For two values of alpha, the vector c DOES lie in span of the vectors a and b.

atjari
 3 years ago
Best ResponseYou've already chosen the best response.0extremly sorry 4 troubling u a lt.

atjari
 3 years ago
Best ResponseYou've already chosen the best response.0Thanx a lt 4 ur great help.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.