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i'm guessing you mean the surface area of the entire cylinder (side and top & bottom) because the rice pudding is only exposed in a disk on top, so a very tall thin cylinder works best to keep your pudding fresh
\[V=\pi r^2 h = 1078\] \[SA= 2\pi r^2 + 2\pi r h=2\pi r(r+h)\]
if you have calculus you can use LaGrange Multipliers or take partial derivatives. If you're only working from Algebra 2 then you need to write h in terms of r (or vice versa) using V so that you can minimize a simple graph in one variable.
so whats the answer
what did you get?
idk what you mean really
are you in calculus? btw my answer was 42*(847pi)^(1/3)
im in grade 9
the answer is supposed to be 5.6cm
what is the height of your cylinder?
No information other than the volume
yah, i have radius of (539/pi)^(1/3) which is 5.55cm or something
are you in algebra 2? ie what book is this from , geometry or algebra
algebra grade 9
are you good with Volume = 1078 = (pi) r^2 h ?
because then h = (1078) / (pi r^2) is your value of h which goes into Surface Area = 2*(pi)*r*h + 2*(pi)*r^2
you're looking for which radius r will minimize surface area, which is 2156/r + 2(pi)r^2
oh ok thank you so much i was having trouble.