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anonymous

  • 4 years ago

a cylinder is being designed to hold rice pudding. it will hold 1078.0 ml of pudding. what radius minimizes the surface area?

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  1. anonymous
    • 4 years ago
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    i'm guessing you mean the surface area of the entire cylinder (side and top & bottom) because the rice pudding is only exposed in a disk on top, so a very tall thin cylinder works best to keep your pudding fresh

  2. anonymous
    • 4 years ago
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    \[V=\pi r^2 h = 1078\] \[SA= 2\pi r^2 + 2\pi r h=2\pi r(r+h)\]

  3. anonymous
    • 4 years ago
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    if you have calculus you can use LaGrange Multipliers or take partial derivatives. If you're only working from Algebra 2 then you need to write h in terms of r (or vice versa) using V so that you can minimize a simple graph in one variable.

  4. anonymous
    • 4 years ago
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    so whats the answer

  5. anonymous
    • 4 years ago
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    what did you get?

  6. anonymous
    • 4 years ago
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    idk what you mean really

  7. anonymous
    • 4 years ago
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    ??????

  8. anonymous
    • 4 years ago
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    are you in calculus? btw my answer was 42*(847pi)^(1/3)

  9. anonymous
    • 4 years ago
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    im in grade 9

  10. anonymous
    • 4 years ago
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    the answer is supposed to be 5.6cm

  11. anonymous
    • 4 years ago
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    what is the height of your cylinder?

  12. anonymous
    • 4 years ago
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    No information other than the volume

  13. anonymous
    • 4 years ago
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    yah, i have radius of (539/pi)^(1/3) which is 5.55cm or something

  14. anonymous
    • 4 years ago
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    are you in algebra 2? ie what book is this from , geometry or algebra

  15. anonymous
    • 4 years ago
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    algebra grade 9

  16. anonymous
    • 4 years ago
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    are you good with Volume = 1078 = (pi) r^2 h ?

  17. anonymous
    • 4 years ago
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    yes,

  18. anonymous
    • 4 years ago
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    because then h = (1078) / (pi r^2) is your value of h which goes into Surface Area = 2*(pi)*r*h + 2*(pi)*r^2

  19. anonymous
    • 4 years ago
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    you're looking for which radius r will minimize surface area, which is 2156/r + 2(pi)r^2

  20. anonymous
    • 4 years ago
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    oh ok thank you so much i was having trouble.

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