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ksaimouli
 4 years ago
x^2x+1/x3 find x intercpts
ksaimouli
 4 years ago
x^2x+1/x3 find x intercpts

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amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2this thing only is zero when the top is zero

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2show you ... what? how to plug values into the quadratic formula? im assuming you know the formula that is

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327858303543:dw

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2\[ax^2+bx+c=0\] \[x=\frac{1}{2a}(b\pm\sqrt{b^24ac})\]

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2which is what completing the square proves ....

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0yes i know this but i dont know hoew to slove this

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2if you know this, then you DO know how to solve this. so whre is the issue?

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0nope i dont know how to slove

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0i just know the formula

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2x^2x+1 define a, b, and c for me from this

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2if drawing helps, by all means :)

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327858568209:dw

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2thats correct so far.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1327858704164:dw

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2\[\frac{1\pm\sqrt{(1)^24(1)(1)}}{2(1)}\] i was assuming a typo lol

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327858744957:dw

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2\[\frac{1\pm\sqrt{(1)^24(1)(1)}}{2(1)}\] \[\frac{1\pm\sqrt{14}}{2}\] \[\frac{1\pm i\sqrt{3}}{2}\]

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2i is a complex number meaning that this has no "real" number solutions

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1there exist no xintercept if you have an imaginary solution to f=0

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2there are no "real" x intercepts, you have a parabola type thing that never touches the x axis

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0ok so no x interscpts if it does not simplyfy

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2http://www.wolframalpha.com/input/?i=%28x%5E2x%2B1%29%2F%28x3%29

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0so when we should use the quadratic formula ?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2if you get complex numbers; which is a sqrt(#) then its not going to ever get intercepted by the x axis

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1when you are solving for x and the equation has this form \[ax^2+bx+c=0\] or can be written in that form

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2just know that there are 3 ways that an outcome can occur

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1one xintercept if b^24ac=0 two xintercepts if b^24ac>0 no xintercepts if b^24ac<0

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2b^24ac =  , no real xints b^24ac = 0, 1 real xint b^24ac = +, 2 real xints

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2i spose i gotta down the chrome; ies slowing up big time

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0ok i got u what in this case 2x^22x3/x

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1just needed a refresh you do the same thing by the way that 2x^22x3 is the top right?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1just plug into the formula amistre gave you

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1factor? There are no two factors of 2(3)=6 that have product 6 and add up to be 2

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0i will plug and give u answer u say me is it right or wrong ok @ mi

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1i will be back after you answer

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0ok 1+0rroot(424)/4

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327859584777:dw

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[x=\frac{(2) \pm \sqrt{(2)^24(2)(3)}}{2(2)}=\frac{2 \pm \sqrt{424}}{4}=\frac{2 \pm \sqrt{20}}{4}\] This can be simplified further

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1327859739220:dw

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1you only made one mistake so far so that is pretty good

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0i have to find xinter right

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1there is no x intercept 20 is a negative number

ksaimouli
 4 years ago
Best ResponseYou've already chosen the best response.0ok got u thx u very mucj @myini
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