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ksaimouli

  • 4 years ago

x^2-x+1/x-3 find x intercpts

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  1. amistre64
    • 4 years ago
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    this thing only is zero when the top is zero

  2. ksaimouli
    • 4 years ago
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    could u show plz

  3. amistre64
    • 4 years ago
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    show you ... what? how to plug values into the quadratic formula? im assuming you know the formula that is

  4. ksaimouli
    • 4 years ago
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    |dw:1327858303543:dw|

  5. ksaimouli
    • 4 years ago
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    nope

  6. amistre64
    • 4 years ago
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    \[ax^2+bx+c=0\] \[x=\frac{1}{2a}(-b\pm\sqrt{b^2-4ac})\]

  7. amistre64
    • 4 years ago
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    which is what completing the square proves ....

  8. ksaimouli
    • 4 years ago
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    yes i know this but i dont know hoew to slove this

  9. amistre64
    • 4 years ago
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    if you know this, then you DO know how to solve this. so whre is the issue?

  10. ksaimouli
    • 4 years ago
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    nope i dont know how to slove

  11. ksaimouli
    • 4 years ago
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    i just know the formula

  12. amistre64
    • 4 years ago
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    x^2-x+1 define a, b, and c for me from this

  13. ksaimouli
    • 4 years ago
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    i will draw ok

  14. amistre64
    • 4 years ago
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    if drawing helps, by all means :)

  15. ksaimouli
    • 4 years ago
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    |dw:1327858568209:dw|

  16. amistre64
    • 4 years ago
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    thats correct so far.

  17. myininaya
    • 4 years ago
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    is it?

  18. myininaya
    • 4 years ago
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    |dw:1327858704164:dw|

  19. amistre64
    • 4 years ago
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    \[\frac{--1\pm\sqrt{(-1)^2-4(1)(1)}}{2(1)}\] i was assuming a typo lol

  20. ksaimouli
    • 4 years ago
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    |dw:1327858744957:dw|

  21. amistre64
    • 4 years ago
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    \[\frac{--1\pm\sqrt{(-1)^2-4(1)(1)}}{2(1)}\] \[\frac{1\pm\sqrt{1-4}}{2}\] \[\frac{1\pm i\sqrt{3}}{2}\]

  22. ksaimouli
    • 4 years ago
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    what is i

  23. amistre64
    • 4 years ago
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    i is a complex number meaning that this has no "real" number solutions

  24. amistre64
    • 4 years ago
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    i = \(\sqrt{-1}\)

  25. ksaimouli
    • 4 years ago
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    so what is x inter

  26. myininaya
    • 4 years ago
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    there exist no x-intercept if you have an imaginary solution to f=0

  27. amistre64
    • 4 years ago
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    there are no "real" x intercepts, you have a parabola type thing that never touches the x axis

  28. ksaimouli
    • 4 years ago
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    ok so no x interscpts if it does not simplyfy

  29. amistre64
    • 4 years ago
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    http://www.wolframalpha.com/input/?i=%28x%5E2-x%2B1%29%2F%28x-3%29

  30. ksaimouli
    • 4 years ago
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    so when we should use the quadratic formula ?

  31. amistre64
    • 4 years ago
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    if you get complex numbers; which is a sqrt(-#) then its not going to ever get intercepted by the x axis

  32. amistre64
    • 4 years ago
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    always

  33. myininaya
    • 4 years ago
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    when you are solving for x and the equation has this form \[ax^2+bx+c=0\] or can be written in that form

  34. amistre64
    • 4 years ago
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    just know that there are 3 ways that an outcome can occur

  35. myininaya
    • 4 years ago
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    one x-intercept if b^2-4ac=0 two x-intercepts if b^2-4ac>0 no x-intercepts if b^2-4ac<0

  36. amistre64
    • 4 years ago
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    b^2-4ac = - , no real xints b^2-4ac = 0, 1 real xint b^2-4ac = +, 2 real xints

  37. amistre64
    • 4 years ago
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    i spose i gotta down the chrome; ies slowing up big time

  38. ksaimouli
    • 4 years ago
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    ok i got u what in this case -2x^2-2x-3/x

  39. ksaimouli
    • 4 years ago
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    x interce

  40. myininaya
    • 4 years ago
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    just needed a refresh you do the same thing by the way that -2x^2-2x-3 is the top right?

  41. ksaimouli
    • 4 years ago
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    yup

  42. ksaimouli
    • 4 years ago
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    we cant factor right

  43. myininaya
    • 4 years ago
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    just plug into the formula amistre gave you

  44. myininaya
    • 4 years ago
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    factor? There are no two factors of -2(-3)=6 that have product 6 and add up to be -2

  45. ksaimouli
    • 4 years ago
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    i will plug and give u answer u say me is it right or wrong ok @ mi

  46. myininaya
    • 4 years ago
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    i will be back after you answer

  47. ksaimouli
    • 4 years ago
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    ok 1+0r-root(4-24)/-4

  48. ksaimouli
    • 4 years ago
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    |dw:1327859584777:dw|

  49. myininaya
    • 4 years ago
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    \[x=\frac{-(-2) \pm \sqrt{(-2)^2-4(-2)(-3)}}{2(-2)}=\frac{2 \pm \sqrt{4-24}}{-4}=\frac{2 \pm \sqrt{-20}}{-4}\] This can be simplified further

  50. ksaimouli
    • 4 years ago
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    after that

  51. myininaya
    • 4 years ago
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    |dw:1327859739220:dw|

  52. myininaya
    • 4 years ago
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    you only made one mistake so far so that is pretty good

  53. ksaimouli
    • 4 years ago
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    i have to find xinter right

  54. myininaya
    • 4 years ago
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    there is no x intercept -20 is a negative number

  55. ksaimouli
    • 4 years ago
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    ok got u thx u very mucj @myini

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