ksaimouli
  • ksaimouli
x^2-x+1/x-3 find x intercpts
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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amistre64
  • amistre64
this thing only is zero when the top is zero
ksaimouli
  • ksaimouli
could u show plz
amistre64
  • amistre64
show you ... what? how to plug values into the quadratic formula? im assuming you know the formula that is

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ksaimouli
  • ksaimouli
|dw:1327858303543:dw|
ksaimouli
  • ksaimouli
nope
amistre64
  • amistre64
\[ax^2+bx+c=0\] \[x=\frac{1}{2a}(-b\pm\sqrt{b^2-4ac})\]
amistre64
  • amistre64
which is what completing the square proves ....
ksaimouli
  • ksaimouli
yes i know this but i dont know hoew to slove this
amistre64
  • amistre64
if you know this, then you DO know how to solve this. so whre is the issue?
ksaimouli
  • ksaimouli
nope i dont know how to slove
ksaimouli
  • ksaimouli
i just know the formula
amistre64
  • amistre64
x^2-x+1 define a, b, and c for me from this
ksaimouli
  • ksaimouli
i will draw ok
amistre64
  • amistre64
if drawing helps, by all means :)
ksaimouli
  • ksaimouli
|dw:1327858568209:dw|
amistre64
  • amistre64
thats correct so far.
myininaya
  • myininaya
is it?
myininaya
  • myininaya
|dw:1327858704164:dw|
amistre64
  • amistre64
\[\frac{--1\pm\sqrt{(-1)^2-4(1)(1)}}{2(1)}\] i was assuming a typo lol
ksaimouli
  • ksaimouli
|dw:1327858744957:dw|
amistre64
  • amistre64
\[\frac{--1\pm\sqrt{(-1)^2-4(1)(1)}}{2(1)}\] \[\frac{1\pm\sqrt{1-4}}{2}\] \[\frac{1\pm i\sqrt{3}}{2}\]
ksaimouli
  • ksaimouli
what is i
amistre64
  • amistre64
i is a complex number meaning that this has no "real" number solutions
amistre64
  • amistre64
i = \(\sqrt{-1}\)
ksaimouli
  • ksaimouli
so what is x inter
myininaya
  • myininaya
there exist no x-intercept if you have an imaginary solution to f=0
amistre64
  • amistre64
there are no "real" x intercepts, you have a parabola type thing that never touches the x axis
ksaimouli
  • ksaimouli
ok so no x interscpts if it does not simplyfy
amistre64
  • amistre64
http://www.wolframalpha.com/input/?i=%28x%5E2-x%2B1%29%2F%28x-3%29
ksaimouli
  • ksaimouli
so when we should use the quadratic formula ?
amistre64
  • amistre64
if you get complex numbers; which is a sqrt(-#) then its not going to ever get intercepted by the x axis
amistre64
  • amistre64
always
myininaya
  • myininaya
when you are solving for x and the equation has this form \[ax^2+bx+c=0\] or can be written in that form
amistre64
  • amistre64
just know that there are 3 ways that an outcome can occur
myininaya
  • myininaya
one x-intercept if b^2-4ac=0 two x-intercepts if b^2-4ac>0 no x-intercepts if b^2-4ac<0
amistre64
  • amistre64
b^2-4ac = - , no real xints b^2-4ac = 0, 1 real xint b^2-4ac = +, 2 real xints
amistre64
  • amistre64
i spose i gotta down the chrome; ies slowing up big time
ksaimouli
  • ksaimouli
ok i got u what in this case -2x^2-2x-3/x
ksaimouli
  • ksaimouli
x interce
myininaya
  • myininaya
just needed a refresh you do the same thing by the way that -2x^2-2x-3 is the top right?
ksaimouli
  • ksaimouli
yup
ksaimouli
  • ksaimouli
we cant factor right
myininaya
  • myininaya
just plug into the formula amistre gave you
myininaya
  • myininaya
factor? There are no two factors of -2(-3)=6 that have product 6 and add up to be -2
ksaimouli
  • ksaimouli
i will plug and give u answer u say me is it right or wrong ok @ mi
myininaya
  • myininaya
i will be back after you answer
ksaimouli
  • ksaimouli
ok 1+0r-root(4-24)/-4
ksaimouli
  • ksaimouli
|dw:1327859584777:dw|
myininaya
  • myininaya
\[x=\frac{-(-2) \pm \sqrt{(-2)^2-4(-2)(-3)}}{2(-2)}=\frac{2 \pm \sqrt{4-24}}{-4}=\frac{2 \pm \sqrt{-20}}{-4}\] This can be simplified further
ksaimouli
  • ksaimouli
after that
myininaya
  • myininaya
|dw:1327859739220:dw|
myininaya
  • myininaya
you only made one mistake so far so that is pretty good
ksaimouli
  • ksaimouli
i have to find xinter right
myininaya
  • myininaya
there is no x intercept -20 is a negative number
ksaimouli
  • ksaimouli
ok got u thx u very mucj @myini

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