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anonymous
 4 years ago
find LCM...10b^4c^9, 2b^6c^8, 15b^7c^6
anonymous
 4 years ago
find LCM...10b^4c^9, 2b^6c^8, 15b^7c^6

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok im confused on how to write the problem out. The way I did it was \[2\times5.b.b.b.b.b.b.b.b.b.b.b.b.b\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the way i did it was what two numbers equal 10 (2x5) then i thought we write out how many b's or c's there are

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0Forget what I wrote previously.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0Instead, think of trying to find the Least Common Denominator

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i did that with each number

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{1}{10b^4c^9}+\frac{1}{2b^6c^8}+\frac{1}{15b^7c^6}\] Imagine you had to add those up. How would you find the LCD?

Hero
 4 years ago
Best ResponseYou've already chosen the best response.030b^7c^9 is the correct answer here.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok i have no clue how you got that lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so the way i was working it, isnt a good way?
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