anonymous
  • anonymous
find LCM...10b^4c^9, 2b^6c^8, 15b^7c^6
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
ok im confused on how to write the problem out. The way I did it was \[2\times5.b.b.b.b.b.b.b.b.b.b.b.b.b\]
anonymous
  • anonymous
the way i did it was what two numbers equal 10 (2x5) then i thought we write out how many b's or c's there are
Hero
  • Hero
Forget what I wrote previously.

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Hero
  • Hero
Instead, think of trying to find the Least Common Denominator
anonymous
  • anonymous
i did that with each number
Hero
  • Hero
\[\frac{1}{10b^4c^9}+\frac{1}{2b^6c^8}+\frac{1}{15b^7c^6}\] Imagine you had to add those up. How would you find the LCD?
anonymous
  • anonymous
would that be 2?
Hero
  • Hero
30b^7c^9 is the correct answer here.
anonymous
  • anonymous
ok i have no clue how you got that lol
anonymous
  • anonymous
so the way i was working it, isnt a good way?

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