## anonymous 4 years ago find LCM...10b^4c^9, 2b^6c^8, 15b^7c^6

1. anonymous

ok im confused on how to write the problem out. The way I did it was $2\times5.b.b.b.b.b.b.b.b.b.b.b.b.b$

2. anonymous

the way i did it was what two numbers equal 10 (2x5) then i thought we write out how many b's or c's there are

3. Hero

Forget what I wrote previously.

4. Hero

Instead, think of trying to find the Least Common Denominator

5. anonymous

i did that with each number

6. Hero

$\frac{1}{10b^4c^9}+\frac{1}{2b^6c^8}+\frac{1}{15b^7c^6}$ Imagine you had to add those up. How would you find the LCD?

7. anonymous

would that be 2?

8. Hero

30b^7c^9 is the correct answer here.

9. anonymous

ok i have no clue how you got that lol

10. anonymous

so the way i was working it, isnt a good way?