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anonymous

  • 4 years ago

let f(x) =3x^3 -5x^2+4x-6 and g(x) = -8x^2-7x +12,evaluate (f.g)(1/2) a.13/8 b.13/6 c.-13/4 d.-13/8

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  1. anonymous
    • 4 years ago
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    lag dont lag this is 2nd to the last question

  2. anonymous
    • 4 years ago
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    im getting error now when it comes to 4x-6 short term memory

  3. anonymous
    • 4 years ago
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    13/6 letter b

  4. anonymous
    • 4 years ago
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    ops w8 wrong theres 1/2

  5. anonymous
    • 4 years ago
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    13/6 sir?

  6. anonymous
    • 4 years ago
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    \[27x-10x+4x =13 16x-7=9 then 9-12=-3 -6-3 =3 f.g(13/3) (1/2)=13/6\]

  7. anonymous
    • 4 years ago
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    ops wrong 1316x =only 13x then 16x-7

  8. anonymous
    • 4 years ago
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    is it b or d

  9. anonymous
    • 4 years ago
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    what is your answer sir?

  10. ash2326
    • 4 years ago
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    we have to find f.g(1/2) let's find f(x).g(x) \[f(x).g(x)=(3x^3-5x^2+4x-6)(-8x^2-7x+12)\] substitute x=1/2 \[f.g(1/2)=(3/8-5/4+4/2-6)(-8/4-7/2+12)\] on solving we get f.g(1/2)=-507/16 not matching any option sorry i'd to go somehere in the middle

  11. ash2326
    • 4 years ago
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    *somewhere

  12. anonymous
    • 4 years ago
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    it will be (-8x-7x)^2 = 8

  13. anonymous
    • 4 years ago
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    -8 or 8

  14. ash2326
    • 4 years ago
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    how 'd you get this?

  15. anonymous
    • 4 years ago
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    im checking my notebook example of my prof XD its not finalized XD

  16. anonymous
    • 4 years ago
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    sqrt of 507 = 13sqrt3

  17. anonymous
    • 4 years ago
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    letter D final not sure

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spraguer (Moderator)
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