let f(x) =3x^3 -5x^2+4x-6 and g(x) = -8x^2-7x +12,evaluate (f.g)(1/2) a.13/8 b.13/6 c.-13/4 d.-13/8

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let f(x) =3x^3 -5x^2+4x-6 and g(x) = -8x^2-7x +12,evaluate (f.g)(1/2) a.13/8 b.13/6 c.-13/4 d.-13/8

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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lag dont lag this is 2nd to the last question
im getting error now when it comes to 4x-6 short term memory
13/6 letter b

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Other answers:

ops w8 wrong theres 1/2
13/6 sir?
\[27x-10x+4x =13 16x-7=9 then 9-12=-3 -6-3 =3 f.g(13/3) (1/2)=13/6\]
ops wrong 1316x =only 13x then 16x-7
is it b or d
what is your answer sir?
we have to find f.g(1/2) let's find f(x).g(x) \[f(x).g(x)=(3x^3-5x^2+4x-6)(-8x^2-7x+12)\] substitute x=1/2 \[f.g(1/2)=(3/8-5/4+4/2-6)(-8/4-7/2+12)\] on solving we get f.g(1/2)=-507/16 not matching any option sorry i'd to go somehere in the middle
*somewhere
it will be (-8x-7x)^2 = 8
-8 or 8
how 'd you get this?
im checking my notebook example of my prof XD its not finalized XD
sqrt of 507 = 13sqrt3
letter D final not sure

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