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anonymous
 4 years ago
limit of (5x+2)/sqrt(9x^2+3x+1)x as x approaches infinity
anonymous
 4 years ago
limit of (5x+2)/sqrt(9x^2+3x+1)x as x approaches infinity

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\text{Limit}\left[\frac{5 x+2}{\sqrt{9 x^2+3 x+1}x},x\to \text{Infinity}\right]=\frac{5}{2} \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0rob its approaching negative infinity

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0also can you please demonstrate in steps. i need to understand how to to dow this. and the denominator is actually sqrt(9x^2+x3) sorry

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0crap let me rewrite the question... i made alot of mistakes

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow infinity}(5x+12)/\sqrt{9x^2+x3}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry. missed the infinity requirement.\[\text{Limit}\left[\frac{5 x+2}{\sqrt{9 x^2+ x3}},x\to \text{Infinity}\right]=\frac{5}{3}=1.6667 \]A plot of the problem expression from 100 throught zero is attached. Cannot help you on the solution process. Using Mathematica for the answers and plot generation.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok this is the last one, do you think you can help me \[\lim_{x \rightarrow infinity}\sqrt{x^2+3x+1}x\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\text{Limit}\left[\sqrt{x^2+3 x+1}x,x\to \text{Infinity}\right]=\frac{3}{2}=1.5 \]Refer to the attached plot.
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