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anonymous
 4 years ago
A cannonball is fired into the air. It's height, h, in metres after t seconds is given by the relation:
h=4.6 (t7.5)^2+285
a) what is the maximum height reached by the cannon and what time is this reached.
b) what was the initial height of the cannon?
c) what is the height of the cannon after 10.5 seconds?
d) how long is the cannon in the air?
anonymous
 4 years ago
A cannonball is fired into the air. It's height, h, in metres after t seconds is given by the relation: h=4.6 (t7.5)^2+285 a) what is the maximum height reached by the cannon and what time is this reached. b) what was the initial height of the cannon? c) what is the height of the cannon after 10.5 seconds? d) how long is the cannon in the air?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Please answer with the steps

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0a) max height is when f'(t)=0 {solve this for t, critical point} i get t=7.6 seconds so max height = h(7.6) b)Initial height is height at t=0. so initial height is h(0) = 26.35feet c) height after 10 seconds = h(10) d)\[\href{ http://www.wolframalpha.com/input/?i=roots+4.6+%28t7.5%29%5E2%2B285+ }{Total time}\] Take positive time
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