A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
find the limit of this please
\[\lim_{x \rightarrow infinity}(5x+12)/\sqrt{9x^2+x3}\]
anonymous
 4 years ago
find the limit of this please \[\lim_{x \rightarrow infinity}(5x+12)/\sqrt{9x^2+x3}\]

This Question is Closed

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[\lim_{x \rightarrow \infty}\frac{5x+12}{\sqrt{9x^2+x3}} \cdot \frac{\frac{1}{\sqrt{x^2}}}{\frac{1}{\sqrt{x^2}}}\] now recall \[\sqrt{x^2}=x=x \text{ if } x<0 \] x<0 since we are approaching negative infinity so we have \[\lim_{x \rightarrow \infty}\frac{5x+12}{\sqrt{9x^2+x3}} \cdot \frac{\frac{1}{x}}{ \frac{1}{\sqrt{x^2}}}\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[\lim_{x \rightarrow \infty} \frac{5+\frac{12}{x}}{\sqrt{9+\frac{1}{x}\frac{3}{x^2}}}\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{5 +0}{\sqrt{9+00}}\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1oops small type0 x=x if x<0

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1everything else is good

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is the final answer 5/sqrt 9

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok i see thanks again myininaya
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.