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anonymous
 4 years ago
find the limit please
\[\lim_{x \rightarrow infinity}\sqrt{x^2+3x+1}x\]
anonymous
 4 years ago
find the limit please \[\lim_{x \rightarrow infinity}\sqrt{x^2+3x+1}x\]

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myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0you should put a 1 underneath that and rationalize the numerator by multiplying top and bottom by the conjugate of the top

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow \infty}\frac{\sqrt{x^2+3x+1}x}{1} \cdot \frac{\sqrt{x^2+3x+1}+x}{\sqrt{x^2+3x+1}+x}\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow \infty}\frac{(x^2+3x+1)x^2}{\sqrt{x^2+3x+1}+x}\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow \infty}\frac{3x+1}{\sqrt{x^2+3x+1}+x} \cdot \frac{\frac{1}{\sqrt{x^2}}}{\frac{1}{\sqrt{x^2}}} \]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0x=x if x>0 which it is since x gets positive large

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow \infty}\frac{3+\frac{1}{x}}{\sqrt{1+\frac{3}{x}+\frac{1}{x^2}}+\frac{x}{x}}\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{3+0}{\sqrt{1+0+0}+1}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this is the last one, can you help me with it please

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Compute A= x^2+x/x+1 as x approaches +infinity and B= x^2+x/x^2+1 as x approaches infinity

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow +\infty} (x^2+x) / (x+1) = +\infty\]\[\lim_{x \rightarrow \infty}(x^2 +x)/(x^2+1) =1\]
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