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EEMajor12
Solve using integrals.
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\[f \prime= dy/dx = 3x^{2}+2/x^2-1\] then separate the variables so that \[\int\limits_{?}^{?}dy = \int\limits_{?}^{?}(3x^2+2/x^2 -1)dx\] then integrate and obtain \[y = x^{3}-2/x -x +c\] substitute in the f(1) = 3 \[3 = 1^{3}-2/1 -1 +c\] so c = 5 then\[f(x) = x^{3}-2/x -x +5 \] \[f(2) = 2^3 -2/2 -2 +5 = 10\]
check answer by taking derivative of f(x) to be sure
@commdoc's solution looks OK.
Thanks for the help guys!